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alina1380 [7]
2 years ago
14

Jason while driving on Kukum highway at 70 m.s – 1 seeing the traffic light turn red, he applies the brake and comes to rest in

a time of 2 seconds. What is his deceleration?
Physics
1 answer:
strojnjashka [21]2 years ago
6 0

Answer:

35 m/s^2

Explanation:

Decceleration =   change in velocity / change in time

                        =  ( 70 m/s ) / 2 seconds = 35 m/s^2

   DEcceleration = 35 m/s^2

       Jason's speed changes by  - 35 m/s^2

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laser pointer does not make use of total internal reflection

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A proton is moving in a circular orbit of radius 12 cm in a uniform 0.31-T magnetic field perpendicular to the velocity of the p
PIT_PIT [208]

Answer:

Explanation:

A proton of charge

q=+1.609×10^-19C

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r=0.12m

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Where m is mass of proton

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Then, F=Fc

qvB sin θ=mv²/r

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rqB=mv

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v=3.58×10^6m/s

b. Since,

F=qVBSin90

F=1.609×10^-19×3.58×10^6×0.31

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6 0
3 years ago
A quantitative description of kinematics involves using ___ th describe the motion
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Answer:

numbers

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4 0
3 years ago
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