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alina1380 [7]
2 years ago
14

Jason while driving on Kukum highway at 70 m.s – 1 seeing the traffic light turn red, he applies the brake and comes to rest in

a time of 2 seconds. What is his deceleration?
Physics
1 answer:
strojnjashka [21]2 years ago
6 0

Answer:

35 m/s^2

Explanation:

Decceleration =   change in velocity / change in time

                        =  ( 70 m/s ) / 2 seconds = 35 m/s^2

   DEcceleration = 35 m/s^2

       Jason's speed changes by  - 35 m/s^2

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Answer:

Acceleration = a = -1.94 m/s^2

Explanation:

Weight of the bundle = W = mg  

                      m = W/g = 473/9.8  

                      m = 48.26 kg

There are two forces acting on the bundle such as tension in the upward direction and weight in the downward direction. So, according to newton’s second law of motion:  

Sum of forces = ma  

                           T - W = ma  

                           a = (T – W)/m

                           a = (379 - 473)/48.26

                           a = -1.94 m/s^2

Negative sign shows that the acceleration is in the downward direction.

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