What do you get when you subtract the force of air resistance from the force of gravity?

2 answers:

5 0

Answer: Net Force, The net force is a single force that replaces the effect of the original forces on the particle's motion. Your answer is Net Force.

atroni [7]3 years ago

3 0

Answer:

Net force

Explanation:

You might be interested in

WHAT IS THE MASS OF AN OBJECT THAT WEIGHS 100 N?

Finger [1]

Answer:

10.2 kg

Explanation:

Assuming the object is on Earth:

w = mg

m = w / g = 100 / 9.81 = 10.2kg

6 0

3 years ago

A 45.0 kg girl is standing on a 159 kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat,

Ganezh [65]

Answer:

(a) $v_g_i=1.08\frac{m}{s}$

(b) $v_p_i=-0.3\frac{m}{s}$

Explanation:

According to the law of conservation of momentum:

$\Delta p=0\\p_i=p_f$

Initially, the girl and the plank are at rest. So, relative to the ice, we have:

$0=m_gv_g_i+m_pv_p_i\\v_p_i=-\frac{m_gv_g_i}{m_p_i}(1)$

(a) The velocity of the girl relative to the ice is:

$v_g_i=v_g_p+v_p_i(2)$

Here, $v_g_p$ is the velocity of the girl relative to the plank and $v_p_i$ is the velocity of the plank relative to the ice.

Replacing (1) in (2):

$v_g_i=v_g_p-\frac{m_gv_g_i}{m_p_i}\\v_g_i+\frac{m_gv_g_i}{m_p_i}=v_g_p\\v_g_i(1+\frac{m_g}{m_p})=v_g_p\\v_g_i=\frac{v_g_p}{1+\frac{m_g}{m_p}}\\v_g_i=\frac{1.38\frac{m}{s}}{1+\frac{45kg}{159kg}}\\v_g_i=1.08\frac{m}{s}$