C6H6 + 15/2O2 = 6CO2 + 3H2O/×2
2C6H6 + 15O2 = 12CO2 + 6H2O
Answer:
D. protons that is the answer
Answer:
The coefficient of O2 is 11
Explanation:
Step 1:
The equation for the reaction:
FeS2 + O2 → SO2 + Fe2O3
Step 2:
Balancing the equation. The equation can be balance as follow:
FeS2 + O2 → SO2 + Fe2O3
There are 2 atoms of Fe on the right side and 1 atom on the left. It can be balance by putting 2 in front of FeS2 as shown below:
2FeS2 + O2 → SO2 + Fe2O3
There are 4 atoms of S on the left side and 1 atom on the right side. It can be balance by putting 4 in front of SO2 as shown below:
2FeS2 + O2 → 4SO2 + Fe2O3
Now, there are a total of 11 atoms of O on the right side and 2 atoms on the left side. It can be balance by putting 11/2 in front of O2 as shown below:
2FeS2 + 11/2O2 → 4SO2 + Fe2O3
Multiply through by 2 to clear the fraction as shown below:
4FeS2 + 11O2 → 8SO2 + 2Fe2O3
Now the equation is balanced.
The coefficient of O2 is 11
2 C3H6 + 2 NH3 + 3 O2 -> 2 C3H3N + 6 H2O
Molar masses
C3H6: 42.08 g/mol
NH3: 17.03 g/mol
O2: 32 g/mol
CH3H3N: 53.06 g/mol
H2O: 18 g/mol
# of moles
C3H6: 15.0 g / [42.08 g/mol] = 0.356 mol
NH3: 5.00 g / [17.03 g/mol] = 0.294 mol
O2: 10.0 g / [32 g/mol] = 0.313 mol
Now wee need to find the limitant reactant
The theoretical proportion is 2:2:3, equivalent to 1:1:1.5
The proportion ot the given gases is 0.356 : 0.294 : 0.313, dividing by 0.294 that is equivalent to: 1.2 : 1 : 1.06, where you see that O2 is below the theoretical proportion and it is the limitant reactant.
Now, from the equation you have 3 mol of O2 produces 2 mol of acrylonitrile (C3H3N)
Then you will obtain 0.313 * 2/3 = 0.209 mol acrylonitrile
The mass is 0.209mol * 53.06 g/mol = 11.07 g acrylonitrile
Answer: 11.07 g
You would weigh the zinc with a weight, Zinc is a mineral so wether it's a solid or a liquid you would measure it with a zinc.