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3 years ago

How can u separate saturated, unsaturated and supersaturated solution?

Chemistry

1 answer:

Kruka [31]3 years ago

4 0

Answer:

Saturated = The solution cannot dissolve any more solute at a given temperature

2) Unsaturated = solution can dissolve more solute at a given temperature.

3) Supersaturated = Solution which has more solute than its saturated solution

Explanation:

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How many grams is 5.8 moles of hydrochloric acid (HCI)? Answer to the nearest 0.01 g.

Anvisha [2.4K]

Answer:

211.47 grams

Explanation:

We need to set up a dimensional analysis to solve this problem by converting from moles to grams.

First, find the molar mass of HCl. Since the molar mass of H (hydrogen) is 1.01 g/mol and the molar mass of Cl (chlorine) is 35.45 g/mol, then the molar mass of HCl is:

1.01 + 35.45 = 36.46 g/mol

We have 5.8 moles of HCl, so multiply by its molar mass:

(5.8 mol) * (36.46 g/mol) = 211.468 ≈ 211.47 g

The answer is thus 211.47 grams.

~ an aesthetics over

8 0

3 years ago

Read 2 more answers

Raw potatoes are composed of about 18%–20% starch and approximately 75% water. Before frying, raw

yarga [219]

You start with 100 kg raw potatoes.

8% of mass is lost by peeling:

100 - ( 8 / 100) × 100 = 92 kg of peeled raw potatoes

By drying the water contents is reduces from 75% to 7%, that means a 68% loss by weight:

92 - ( 68 / 100) × 92 = 92 - 62.56 = 29.44 kg of dried potatoes

4 0

4 years ago

Gas occupies 2.5 L at 2.5 atm. What is the volume if the pressure changes to 1.5 atm?

fenix001 [56]

Answer:

dont know

Explanation:

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3 years ago

Complete and balance the following redox reaction in acidic solution As2O3(s) + NO3- (aq) → H3AsO4(aq) + N2O3(aq)

scoray [572]

Answer:

$As_{2}O_{3}(s)+2NO_{3}^{-}(aq)+2H_{2}O(l)+2H^{+}(aq)\rightarrow 2H_{3}AsO_{4}(aq)+N_{2}O_{3}(aq)$

Explanation:

Oxidation: $As_{2}O_{3}(s)\rightarrow H_{3}AsO_{4}(aq)$

Balance As: $As_{2}O_{3}(s)\rightarrow 2H_{3}AsO_{4}(aq)$
Balance H and O in acidic medium: $As_{2}O_{3}(s)+5H_{2}O(l)\rightarrow 2H_{3}AsO_{4}(aq)+4H^{+}(aq)$
Balnce charge: $As_{2}O_{3}(s)+5H_{2}O(l)-4e^{-}\rightarrow 2H_{3}AsO_{4}(aq)+4H^{+}(aq)$ ......(1)

Reduction: $NO_{3}^{-}(aq)\rightarrow N_{2}O_{3}(aq)$

Balance N: $2NO_{3}^{-}(aq)\rightarrow N_{2}O_{3}(aq)$
Balance H and O in acidic medium: $2NO_{3}^{-}(aq)+6H^{+}(aq)\rightarrow N_{2}O_{3}(aq)+3H_{2}O(l)$
Balance charge: $2NO_{3}^{-}(aq)+6H^{+}(aq)+4e^{-}\rightarrow N_{2}O_{3}(aq)+3H_{2}O(l)$ ......(2)