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3 years ago

Find the equation of the tangent line. y=(9-x^2)^1/3 at (1,2)

Mathematics

1 answer:

Schach [20]3 years ago

7 0

Get the derivative:

y = (9 - x²)¹ʹ³

dy/dx = 1/3 (9 - x²)⁻²ʹ³ d/dx [9 - x²]

dy/dx = 1/3 (9 - x²)⁻²ʹ³ (-2x)

dy/dx = -2/3 x (9 - x²)⁻²ʹ³

Evaluate it at x = 1 :

dy/dx (1) = -2/3 • 8⁻²ʹ³

Since 8 = 2³, we have

8⁻²ʹ³ = 1 / 8²ʹ³ = 1 / (2³)²ʹ³ = 1 / 2² = 1/4

Then the tangent line has equation

y - 2 = 1/4 (x - 1) → y = 1/4 x + 7/4

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irga5000 [103]

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3 years ago

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3 years ago

Read 2 more answers

Type the correct answer in each box. Use numerals instead of words. For this question, any answer that is not a whole number sho

egoroff_w [7]

Answer:

Step-by-step explanation:

Since we are not given the value of P, |Q|, R and S, we can as well assume values for them for the sake of this question.

Let P = 5, |Q| = 6, R =7 |S| = 2

Note that since Q and S are in modulus sign, they can return both positive and negative values.

P+Q = 5 + 6 (note that the positive value of Q is used since we need the greatest value of P+Q)

P+Q = 11

Hence the greatest value of P+Q is 11

For the least value of P+Q, we will use the negative value of Q as shown

P+Q = 5+(-6)

P+Q = 5-6

P+Q = -1

Hence the least value of P+Q is -1

Similarly:

R+S = 7 + 2 (note that the positive value of S is used since we need the greatest value of R+S)

R+S = 9

Hence the greatest value of R+S is 9

For the least value of R+S, we will use the negative value of S as shown

R+S = 5+(-2)

R+S = 5-3

R+S = 2

Hence the least value of P+Q is 2

NOTE THAT THIS ARE ASSUMED VALUES. ALL YOU NEED IS TO PLUG IN THE VALUES OF P, Q and R THAT YOU HAVE IN CASE THE VALUES DIFFERS.

5 0

3 years ago

Simplify (3/2x+5) + (5/x-5)

tia_tia [17]

Answer:

(3x + 10) / (2x + 5)(x - 5).

Step-by-step explanation:

(3/2x+5) + (5/x-5)

= [3(x - 5) + 5(2x + 5) ] / [ (2x + 5)(x - 5)]

= 3x - 15 + 10x + 25 / (2x + 5)(x - 5)

= 13x + 10 / (2x + 5)(x - 5).

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3 years ago

It takes Santa 5 minutes to fly 35 miles with the wind .It takes him 7 minutes to fly 35 miles against the wind determine the sp

Dmitrij [34]

Answer: Santa's speed in still air is 6 miles per minute

Speed of the wind is 1 mile per minute

Step-by-step explanation:

Let x represent the speed of Santa in still air. It is assumed that in still air. She is flying with the wind. If the speed of the wind is y, then him total speed is x + y

It takes Santa 5 minutes to fly 35 miles with the wind.

Speed = distance / time

It means that

x + y = 35/5 = 7

It takes him 7 minutes to fly 35 miles against the wind. This means that his total speed will be x - y

Speed = distance/time. Therefore,

x - y = 35 /5 = 5 - - - - - - 1

Substituting x = 7 - y into equation 1, it becomes

7 - y - y = 5

-2y = 5 - 7 = -2

y = -2/-2 = 1

x = 7 - y = 7 - 1

x = 6

3 0

3 years ago

Find the equation of the tangent line. y=(9-x^2)^1/3 at (1,2)​

Find the equation of the tangent line. y=(9-x^2)^1/3 at (1,2)