Answer:
- import java.util.Scanner;
- import java.util.Random;
- public class Main {
-
- public static void main(String[] args) {
-
- Scanner input = new Scanner(System.in);
- Random rand = new Random();
-
- System.out.print("Enter number of questions you wish to practice: ");
- int n = input.nextInt();
-
- int i = 1;
- while(i <= n){
- int num1 = 1 + rand.nextInt(10);
- int num2 = 1 + rand.nextInt(10);
- int answer = num1 * num2;
- System.out.print("Question " + i + ": " + num1 + " x " + num2 + " = ");
- int response = input.nextInt();
-
- if(response == answer){
- System.out.println("Correct answer!");
- }
- else{
- System.out.println("Wrong answer. It should be " + answer);
- }
- i++;
- }
- }
- }
Explanation:
Firstly, we import Scanner and Random classes (Line 1-2) as we need to get user input for number of questions and generate random number in each question.
Next, create a Scanner and Random object (Line 7-8). Prompt user to input number of question and get the input using the Scanner object (Line 10-11).
Next create a while loop and set the condition to loop for n number of times (based on number of questions) (Line 14). In the loop, use Random object nextInt method to generate two integers between 1 -10 (Line 15-16). Prompt user to input an answer using the Scanner object (Line 18-19). If the response is matched with answer print a correct message (Line 21-22) other wise inform user they write a wrong answer and show the correct answer (Line 24-25).
Answer:
(a) We are asked to compute the Brinell hardness for the given indentation. for HB, where P= 1000 kg, d= 2.3 mm, and D= 10 mm.
Thus, the Brinell hardness is computed as
![=2*1000hg/\pi (10mm)[10mm-\sqrt{(1000^2-(2.3mm)^2} ]](https://tex.z-dn.net/?f=%3D2%2A1000hg%2F%5Cpi%20%2810mm%29%5B10mm-%5Csqrt%7B%281000%5E2-%282.3mm%29%5E2%7D%20%5D)
(b) This part of the problem calls for us to determine the indentation diameter d which will yield a 270 HB when P= 500 kg.
![d=\sqrt{D^2-[D-\frac{2P}{(HB)\pi D} } ]^2\\=\sqrt{(10mm)^2-[10mm-\frac{2*500}{450( \pi10mm)} } ]^2](https://tex.z-dn.net/?f=d%3D%5Csqrt%7BD%5E2-%5BD-%5Cfrac%7B2P%7D%7B%28HB%29%5Cpi%20D%7D%20%7D%20%5D%5E2%5C%5C%3D%5Csqrt%7B%2810mm%29%5E2-%5B10mm-%5Cfrac%7B2%2A500%7D%7B450%28%20%5Cpi10mm%29%7D%20%7D%20%5D%5E2)
Answer:
C. Homeowners
Explanation:
I just took my automotive pollution prevention certification and passed by answering homeowners for this question.
An isometrical drawing is a nearly 3d drawing showing the object's width and depth in a complete image, from each curved plane of the orthhographic view, the viewpoint is at a 45 degree angle. From an observations point of view, isometric differs, since all longitudes are true.
