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3 years ago

Another problem I can’t solve is

Mathematics

1 answer:

Ganezh [65]3 years ago

8 0

So what you would do is you would divide 27 by 12. Your answer would be 2.25. They used 2.25 pounds per sandwich.

Hope that helps!

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How many ft2 are in a rectangle 12.6 yd long and 8.6 yd wide? (A = lw)

Usimov [2.4K]

Answer:

108.36 ft2

Step-by-step explanation:

Use the facts we already know and plug them into the equation.

a=12.6(8.6)

If we multiply both factors, we get 108.36.

So, the rectangle is 108.36 ft2

3 0

4 years ago

Write the equation in standard form for the circle with radius 9 centered at the origin.

amid [387]

The standard form of the equation of a circle of radius r, with (assuming centre h, k) is given as:

(X-h)^2 + (y-k)^2 = r^2

As we are required to write an equation in standard form for the circle with radius 9 centred at the origin.
Centre(h,k)=(0,0), r=9

Substituting these values into the standard form of the equation of a circle given above:

(X-0)^2 + (y-0)^2 = 9^2
X^2 + y^2 =81

The standard form is x^2 + y^2 =81

I’m pretty sure this is right

8 0

3 years ago

Please answer asap!!!! will mark brainiest

Inga [223]

Answer:

x=2

Step-by-step explanation:

We know the only number that gets us back to 0 after subtracting 4 is 4, because 4-4=0. The square root of 4 is 2. Hope my explanation wasn't too confusing!

2²=4

4-4=0

3 0

4 years ago

Read 2 more answers

Determine the longest interval in which the given initialvalue problemis certainto have a unique twicedifferentiable solution. D

AlekseyPX

Answer:

t_o = 3, so solution exists on (0,4).

Step-by-step explanation:

Use Theorem

Divide equation with t(t — 4).

y''+[3/(t-4)]*y'+ [4/t(t-4)]*y=2/t(t-4)

p(t)=3/t-4—> continuous on (-∞, 4) and (4,∞)

q(t) = 4/t(t-4) —> continuous on (-∞,0), (0,4) and (4, ∞)

g(t) = 2/t(t-4)—> continuous on (-∞, 0), (0,4) and (4,∞)

t_o = 3, so solution exists on (0,4).

6 0

3 years ago

Write 543.24 in expanded form.

tekilochka [14]

Answer:

543.24

Step-by-step explanation:

Expanded Notation Form:

500

+ 40

+ 3

+ 0.2

+ 0.04

Expanded Factors Form:

5 × 100

+ 4 × 10

+ 3 × 1

+ 2 × 0.1

+ 4 × 0.01

Expanded Exponential Form:

5 × 102

+ 4 × 101

+ 3 × 100

+ 2 × 10-1

+ 4 × 10-2

Word Form:

five hundred forty-three and twenty-four hundredths

7 0

3 years ago