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mrs_skeptik [129]
3 years ago
13

Va box contains 4 red marbles and 7 green remove 3 at once probability of 3 red

Mathematics
1 answer:
lbvjy [14]3 years ago
3 0

Answer:

0.024

Step-by-step explanation:

Given,

Red marbles = 4,

Green marbles = 7,

Total marbles = 4 +7 = 11,

Ways of choosing 3 marbles =^{11}C_3

Ways of choosing 3 red marble = ^4C_3

Hence, the probability of 3 red marble = \frac{^4C_3}{^{11}C_3}

=\frac{\frac{4!}{3!1!}}{\frac{11!}{3!8!}}

=\frac{4}{165}

≈ 0.024

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