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abruzzese [7]
3 years ago
9

Recall the raisin cake model of the universe. Our universe is expanding between the galaxies. You measure the recession velocity

of Galaxy A to be 2,000 km/sec and the recession velocity of Galaxy B to be 6,000 km/sec. What can you say about the distances to these galaxies?
Physics
1 answer:
Rina8888 [55]3 years ago
5 0

Explanation:

Recession velocity of a galaxy is related to the distance at which the galaxy is located. This relationship is given by the hubble constant, as follows:

v_r=HD

Hubble constant is aproximate 70\frac{km/s}{Mpc} and 1 megaparsec (Mpc) is 3.26*10^6 light years. Rewriting for D:

D=\frac{v_r}{H}

For galaxy A:

D=\frac{2000\frac{km}{s}}{70\frac{km/s}{Mpc}}\\\\D=28.57Mpc\\\\D=28.57Mpc*\frac{3.26*10^6ly}{1Mpc}=9.31*10^7ly

For galaxy B:

D=\frac{6000\frac{km}{s}}{70\frac{km/s}{Mpc}}\\\\D=85.71Mpc\\\\D=85.71Mpc*\frac{3.26*10^6ly}{1Mpc}=2.79*10^8ly

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. If you live in a region that has a particular TV station, you can sometimes pick up some of its audio portion on your FM radio
Reil [10]

Answer:

Please see below as the answer is self-explanatory.

Explanation:

The low band of the VHF TV Spectrum, spans channels 2-6, from 54 to 88 Mhz.

In the analog TV, in the Americas, the total bandwidth of any channel is 6 Mhz, with the visual carrier modulated in VSS (Vestigial Side Band) at 1.25 Mhz from the lowest frequency of the channel.

The aural carrier is located at 4.5 Mhz from the visual carrier, and is FM modulated.

For Channel 6, which spans between 82 and  88 Mhz, the visual carrier is at 83.25 Mhz, so the aural carrier is at 87.75 Mhz, which falls within the FM Band, so it is possible to listen the audio part of this channel in a FM radio receiver, even at a lower volume, due to the FM radio has a greater deviation than TV aural carrier.

6 0
4 years ago
If the velocity of a moving object decreases from 60 m/s to 30 m/s, what happens to its momentum?
amid [387]

Hello!

momentum is p=mv so if the velocity is decreased by a factor of 2, which is 1/2 the value, then the momentum of that object will decrease by the same factorial.

Hope this helps, any questions please ask. Thank you!

6 0
4 years ago
Read 2 more answers
A family car has a mass of 1400 kg. In an accident it hits a wall and goes from a speed of 27 m/s to a standstill in 1.5 seconds
horrorfan [7]

Answer:

The force has been reduced by 8018 N

Explanation:

The impulse exerted on the car during the crash is equal to the product of the force exerted and the duration of the collision, and it is also equal to the change in momentum of the car. So we can write:

F\Delta t = m\Delta v

where:

F is the force exerted on the car

\Delta t is the duration of the collision

m = 1400 kg is the mass of the car

\Delta  v=-27 m/s is the change in velocity of the car

We can re-write the equation as

F=\frac{m\Delta v}{\Delta t}

In the 1st collision, the time is 1.5 seconds, so the force is

F_1=\frac{(1400)(-27)}{1.5}=-25,200 N

In the 2nd collision, the time is increased to 2.2 seconds, so the force is

F_2=\frac{(1400)(-27)}{2.2}=-17,182 N

Therefore, the force has been reduced by:

F_2-F_1=-17,182-(-25,200)=8018 N

4 0
4 years ago
Read 2 more answers
Consider a perfectly reflecting mirror oriented so that solar radiation of intensity i is incident upon, and perpendicular to, t
podryga [215]
The answer is Frad<span> = 2IA/c.</span>
4 0
4 years ago
Read 2 more answers
If 90 grams of gold has a volume of 5 cm3, calculate the density (include the units and show your work or you get no credit
ehidna [41]

Answer:

The density of gold is of 18 grams per cm3.

Explanation:

The mass density of a homogeneous material expresses how much mass of that material is present in a given volume. Since the density of an object is obtained by dividing its mass by its volume, to obtain the density of gold, its 90 grams of mass must be divided by its 5 cm3 volume, performing the following calculation:

90/5 = X

18 = X

Thus, the density of gold is 18 grams per cm3.

6 0
3 years ago
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