Answer:
Fx = 32.14 [N]
Fy = 38.3 [N]
Explanation:
To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.
F = 50 [N]
Fx = 50*cos(50) = 32.14 [N]
Fy = 50*sin(50) = 38.3 [N]
We can verify this result using the Pythagorean theorem.
![F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N]](https://tex.z-dn.net/?f=F%20%3D%20%5Csqrt%7B%2832.14%29%5E%7B2%7D%2B%20%2838.3%29%5E%7B2%7D%7D%20%5C%5CF%20%3D%2050%20%5BN%5D)
Explanation:
Number 29
= 10 N (from rocket) + 10 N (from wheels) - 7 N (from parachute 'cause force in other direction)
= 20 N - 7 N
= 13 N ✔
Number 30
= 100 N - 85 N
= 15 N to the left ✔
Answer:
Cart A will bounce to the left while cart B will move right at less than 2 meters per second
Explanation:
Answer:
we must multiply the speed value by 3.6
Explanation:
To reduce a magnitude from one unit to another, it must be multiplied by the equivalence in the order necessary so that the units do not change.
To reduce speed from m / s to km / h
we write the speed and the two conversion factors
v [m / s] [1 km / 1000m] [3600 s / 1h
v 3600/1000
v 3.6
therefore we must multiply the speed value by 3.6
Answer:
Amount of radioactive particles left after 60 years = 100 particles.
Explanation:
Amount of radioactive particles before 60 years = 400
Amount of radioactive particles present today = 200
That is radio active particles reduced to half. That is 60 years is half life of this radio active material.
After 60 years this 200 radio active particles will reduce to half.
Amount of radioactive particles left after 60 years = 0.5 x 200 = 100 particles.
