Question

A pendulum is swinging back and forth with a period of 2.0 seconds here on Earth. This pendulum is then brought to the Moon, where the acceleration due to gravity is much smaller. What will happen to the period of the pendulum, assuming everything else about it (mass, length, initial swing height, etc) remains exactly the same? Explain your answer.
Please. I really need help.

Answer 1

Answer: The period of the pendulum will be bigger than in Earth.

Explanation:

The period of a pendulum is:

T = 2*pi*√(L/g)

where pi = 3.14

L is the length of the pendulum and g is the gravitational acceleration.

you can see that g is in the denominator, so if g is smaller, then the end number woll be bigger (because in the moon we are dividing by a smaller number)

This means that in the moon the period of the pendulum is bigger than in the Earth.