The correct answer is 0.67 h
The coil's induced emf is specified as e=0. 50 v.
i i = 0.55 A is the initial value of the current flow.
I f = 0.95 A is the total amount of current flowing.
The shift in current occurs in a period of time when dt = 0.40 s.
The self-inductance is determined as follows:
The current change rate is represented here by dI/dt.
Step 2 After entering the values,
As a result, the self-inductance is 0.67 H.
The definition of self inductance is the induction of a voltage in a wire that carries current when the current in the wire is changing. When there is self-inductance, a circuit's own changing current creates a magnetic field that causes a voltage to be induced.
Learn more about Self inductance here :-
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Ben was trying to <span>increase fluid friction. </span>
Answer:
No ejection of photo electron takes place.
Explanation:
When a photon of suitable energy falls on cathode, then the photoelectrons is emitted from the cathode. This phenomenon is called photo electric effect.
The minimum energy required to just eject an electron is called work function.
The photo electric equation is
E = W + KE
where, E is the incident energy, W is the work function and KE is the kinetic energy.
W = h f
where. h is the Plank's constant and f is the threshold frequency.
Now, when the violet light is falling, no electrons is ejected. When the red light is falling, whose frequency is less than the violet light, then again no photo electron is ejected from the metal surface.
Answer:
static electricity is built up of charges on an object
