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IgorLugansk [536]
3 years ago
10

Suppose you place an ice cube into a cup of hot tea? What will happen to the temperature of the ice cube and the tea? A) The tem

perature of the ice will increase quickly, while the temperature of the tea will drop slowly. The liquids may or may not reach equilibrium. B) The temperature of the tea will drop quickly, while the temperature of the ice will increase slowly. The liquids may or may not reach equilibrium. C) The ice will melt and the temperature of the tea will drop quickly; then the change will slow until equilibrium is reached. D) The temperature of the ice will rise slowly at first and the temperature of the tea will drop slowly; then the temperature change quicken until equilibrium is reached.
Chemistry
1 answer:
Ksivusya [100]3 years ago
8 0

Answer:

The answer is D

Explanation:

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Elements K and L have 12 and 17 protons respectively. If k has 24 neutrons and L has 36, in a tabular form identify the number o
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Answer: try watchong videos search up what you just say and wtch the videos it could help

Explanation:

5 0
3 years ago
How old is a bone if it now .3125 of C-14 when it originally had 80.0g of C-14
Taya2010 [7]
<h3>Answer:</h3>

42960 years

<h3>Explanation:</h3>

<u>We are given;</u>

  • Remaining mass of C-14 in a bone is 0.3125 g
  • Original mass of C-14 on the bone is 80.0 g
  • Half life of C-14 is 5370 years

We are required to determine the age of the bone;

  • Using the formula;
  • Remaining mass = Original mass × 0.5^n , where n is the number of half lives.

Therefore;

0.3125 g = 80.0 g × 0.5^n

3.90625 × 10^-3 = 0.5^n

  • Introducing logarithm on both sides;

log 3.90625 × 10^-3 = n log 0.5

Solving for n

n = log 3.90625 × 10^-3 ÷ log 0.5

   = 8

  • Therefore, the number of half lives is 8
  • But, 1 half life is 5370 years
  • Therefore;

Age of the rock = 5370 years × 8

                          = 42960 years

Thus, the bone is 42960 years old

7 0
3 years ago
The last intermediate in citric acid cycle is:_________
GenaCL600 [577]

The last intermediate in citric acid cycle is Oxaloacetic acid.

<h3>What is Citric Acid Cycle?</h3>

Organic molecule HOC(CO2H)(CH2CO2H)2 is the chemical formula for citric acid. It is a weak organic acid that is colorless. Citrus fruits naturally contain it. It is a biochemical intermediary in the citric acid cycle, which is a component of all aerobic organisms' metabolism.

Every year, more than two million tons of citric acid are produced. It is frequently used as a flavoring, an acidifier, and a chelating agent.

Citrates, which include salts, esters, and the polyatomic anion present in solution, are derivatives of citric acid. Trisodium citrate is an example of the former; triethyl citrate is an example of an ester.

Learn more about citric acid with the help of the given link:

brainly.com/question/15582668

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7 0
1 year ago
In the alkane series of hydrocarbons, as the number of carbon atoms decreases, the normal boiling point ofthe compounds
noname [10]
<span>The relationship between the number of carbon atoms and boiling point is inversely proportional. In the alkane series of hydrocarbons, as the number of carbon atoms decreases, the normal boiling point of the compounds decreases. The reason behind this is that longer chains of molecules require more energy to separate the bonds while shorter chains or molecules with lower number of carbon atoms require less energy to break away from each other. Thus, low carbon molecules have lower boiling point.</span>
3 0
3 years ago
Formaldehyde is a carcinogenic volatile organic compound with a permissible exposure level of 0.75 ppm. At this level, how many
Flauer [41]

Answer : The amount of formaldehyde permissible are, 5.4\times 10^{-6}g

Explanation : Given,

Density of air = 1.2kg/m^3=1.2g/L     (1kg/m^3=1g/L)

First we have to calculate the mass of air.

\text{Mass of air}=\text{Density of air}\times \text{Volume of air}

\text{Mass of air}=1.2g/L\times 6.0L

\text{Mass of air}=7.2g

Now we have to calculate the amount of formaldehyde.

Permissible exposure level of formaldehyde = 0.75 ppm = \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}

Amount of formaldehyde in 7.2 g of formaldehyde = 7.2g\times \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}

Amount of formaldehyde in 7.2 g of formaldehyde = 5.4\times 10^{-6}g

Thus, the amount of formaldehyde permissible are, 5.4\times 10^{-6}g

8 0
3 years ago
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