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Zanzabum
3 years ago
5

Identify each energy exchange as primarily heat or work and determine whether the sign of ΔE is positive or negative for the sys

tem. a. A rolling billiard ball collides with another billiard ball. The first billiard ball (defined as the system) stops rolling after the collision. b. A book falls to the floor. (The book is the system). c. A father pushes his daughter on a swing. (The daughter and the swing are the system)
Chemistry
1 answer:
Semmy [17]3 years ago
8 0

Answer:

a. Work, ΔE is negative;

b. Work, ΔE is negative;

c. Work, ΔE is positive.

Explanation:

In the three cases, there is energy exchange in primarily work. The heat is the energy flow because of the difference in temperature. Of course, some heat may be lost in the cases by dissipation.

In the letter <em>a</em> the system is at an initial velocity different from 0, and then it stops. The energy that is represented here is the kinetic energy, which is the energy of the movement. Note that the system goes from a higher velocity to 0, so it is losing kinetic energy, or work, so ΔE = Efinal - Einitial < 0.

In letter <em>b</em>, the system is falling from a certain high to the floor, so its gravitational potential energy is change. That potential energy represents the energy that gravity does when an object shifts vertically. Because it goes from a high to 0, the energy is been lost, so ΔE = Efinal - Einitial < 0.

In letter <em>c</em>, the system is going higher and with higher velocity, so there is a greatness in the gravitational potential energy and the kinetic energy, both works, so ΔE = Efinal - Einitial > 0.

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A volume of 60.0 mL of a 0.120 M HNO3 solution is titrated with 0.840 M KOH. Calculate the volume of KOH required to reach the e
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Answer: 8.57 ml of KOH is required to reach the equivalence point.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.120M\\V_1=60.0mL\\n_2=1\\M_2=0.840M\\V_2=?

Putting values in above equation, we get:

1\times 0.120\times 60.0=1\times 0.840\times V_2\\\\V_2=8.57mL

Thus 8.57 ml of KOH is required to reach the equivalence point.

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4 years ago
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The product of this reaction emits red light because it absorbs green and blue light. As the reaction occurs, the concentration of the product increase. This will makes absorbance of green and blue light increases and the solution will become redder.</span>
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3 years ago
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Answer:see attached image

Explanation:

In organic chemistry, a product may be kinetically or thermodynamically favoured. A kinetically favours product forms faster, it may not necessarily be the more stable product. The thermodynamically favoured product forms at a slower rate but is more stable. Often times, the kinetically favoured product rearranges itself to form the thermodynamically favoured product at equilibrium. The endo product of the Diels Alder reaction mentioned in the question is first formed (kinetically favoured) but rearranges to form the exo product (thermodynamically favoured) at equilibrium. This is clear shown in the reaction mechanism attached below.

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The chemical equation is:

<span>HCO3^    ->  H^+ + CO3^2- </span>

 

We know that the formula for Ka is:
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Answer:

<span>2.636</span>

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