Ask question

Ask question

All categories

3 years ago

7

Which of the following best represents the general form of a chemical equation?

1 answer:

satela [25.4K]3 years ago

4 0

The general form would be
Reactants ---> Products

You might be interested in

A balloon, whose volume at 23°C is 535 mL, is heated to 46°C. Assuming the pressure and amount of gas remain constant, what is t

NikAS [45]

This problem requires a certain equation. That equation is V1/T1=V2/T2, where V1 is your initial volume (535 mL in this case), T1 is your initial temperature in Kelvin(23 degrees C = 296 K), V2 is your final volume (unknown), and T2 is your final temperature (46 degrees C = 319 K). By plugging in these values, the equation looks like this: 535/296=V2/319. Now multiply both sides of the equation by 319, and your final answer is V2= 576.6 mL

5 0

3 years ago

Read 2 more answers

which method would be best for separating the compounds of a mixture that is made from two diffrent liquids

kobusy [5.1K]

Answer:

fractional distillation since ot depends on the different liquids to have different boiling points

5 0

2 years ago

klio [65]

Answer:

Vascular plants are successful due to better transportation for water, nutrients and reproduction.

Explanation:

I got it right at school and hope this helps you learn to STUDY.jk

6 0

3 years ago

Ocean water Choose one: A. is less dense than freshwater. B. salinity decreases as seawater evaporates. C. contains dissolved sa

Genrish500 [490]

Answer: the answer is C

Explanation:

8 0

2 years ago

The concentration of Rn−222 in the basement of a house is 1.45 × 10−6 mol/L. Assume the air remains static and calculate the con

bonufazy [111]

<u>Answer:</u> The concentration of radon after the given time is $3.83\times 10^{-30}mol/L$

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

We are given:

$t_{1/2}=3.82days$

Putting values in above equation, we get:

$k=\frac{0.693}{3.82}=0.181days^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.181days^{-1}$

t = time taken for decay process = 3.00 days

$[A_o]$ = initial amount of the reactant = $1.45\times 10^{-6}mol/L$

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}$

$[A]=3.83\times 10^{-30}mol/L$

Hence, the concentration of radon after the given time is $3.83\times 10^{-30}mol/L$

7 0

3 years ago