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omeli [17]
3 years ago
9

Question 25

Mathematics
1 answer:
AysviL [449]3 years ago
8 0

Answer:

120

Step-by-step explanation:

First, you have to calculate the money that Seth would spent if he goes to 30 movies if his father gets the summer movie pass by adding up the cost of the pass plus the result of multiplying the cost per movie with the pass for the number of movies:

30+(3*30)=30+90=120

Second, you need to calculate the money that Seth would spent if he goes to 30 movies without the pass by multiplying the normal price per movie for the number of movies:

8*30=240

Third, you need to find the difference between both costs:

240-120=120

According to this, the answer is that if Seth plans to go to 30 movies this summer, he would save 120.

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Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)
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sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

<u>Step-by-step explanation:</u>

We need to find sum of sequence  : 46 + 42 + 38 + ... + (-446) + (-450)

Given sequence is an AP with following parameters as :

a=46\\d=42-46=-4

So , Let's calculate how many terms are there as :

⇒ a_n=a +(n-1)d

⇒ -450=46 +(n-1)(-4)

⇒ -496=(n-1)(-4)

⇒ \frac{-496}{-4}=n-1

⇒ 124=n-1

⇒ n=125

Sum of an AP is :

⇒ S_n = \frac{n}{2}(2a+(n-1)d)

⇒ S_1_2_5 = \frac{125}{2}(2(46)+(125-1)(-4))

⇒ S_1_2_5 = \frac{125}{2}(-404)

⇒ S_1_2_5 =-25,250

Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

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