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3 years ago

11

What is the solution of the inequality

1 answer:

sesenic [268]3 years ago

8 0

Answer:

$- 0.4x - 1.2 > 0.8$

$- 0.4x > 0.8 + 1.2$

$- 0.4x > 2$

WE DIVIDE BY A NEGATIVE NUMBER!!!!

$x < \frac{2}{ - 0.4}$

$x < - 5$

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The formula for the surface area of a cube is SA=6s2, where is a is the length of one side of the cube if s=1/4 of a unit, what

aksik [14]

<h2>The surface area of the cube is 0.375 square units.</h2>

Step-by-step explanation:

Given : The formula for the surface area of a cube is $SA=6s^2$ , where s is the length of one side of the cube if $s=\frac{1}{4}$ of a unit.

To find : What is the surface area, in square units, of the cube?

Solution :

The formula for the surface area of a cube is $SA=6s^2$

We have given, $s=\frac{1}{4}$

Substitute in the formula,

$SA=6(\frac{1}{4})^2$

$SA=6\times \frac{1}{16}$

$SA= \frac{3}{8}$

$SA=0.375$ square units.

Therefore, the surface area of the cube is 0.375 square units.

5 0

3 years ago

17) If your GROSS INCOME is $90,000 and you have 33% in TAXES

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60,000 nnnmmmmmmmmmm

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3 years ago

The profits earned in a year by some companies in a city are shown below:

bekas [8.4K]

Median, because there is an outlier that affects the mean

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3 years ago

All three sides of a triangle are initially 4 m in length. One of the triangle's sides is oriented horizontally. The triangle is

Arlecino [84]

Answer:

the new height of the triangle = 2.449

Step-by-step explanation:

Given that:

the sides of the triangle are 4m in length i.e they are equal. It shows that the triangle is known to be an equilateral triangle.

Let say the triangle is a triangle IJK

Let the length of the side to be i = 4

Definitely

IJ = JK = IK = i = 4

If a midline is drawn and cuts the equilateral triangle in two equal halves of a right-angle triangle. Then, suppose the midline is L

Then ;

$JL = \dfrac{1}{2} JK$

$JL = \dfrac{1}{2} i$

Let consider triangle IJL

(IL)² = (IJ)² - (JL)²

$(IL)^2 = i^2 - \dfrac{i^2}{4}$

$(IL)^2 = \dfrac{3i^2}{4}$

$(IL) =\sqrt{ \dfrac{3i^2}{4}}$

$IL =\sqrt{3} \dfrac{i}{2}$

Area of triangle IJK can be expressed as:

$Area = \dfrac{1}{2}\times Base \times Height$

$Area = \dfrac{1}{2}\times i \times \sqrt{3}\dfrac{i}{2}$

$Area = \sqrt{3}\dfrac{i^2}{4}$

where, i = 4

Then:

$Area = \sqrt{3}\dfrac{4^2}{4}$

$Area = \sqrt{3} \dfrac{16}{4}$

$Area =4 \sqrt{3}$

when the area is exactly half of the original triangle's area, the new height is :

$A = \dfrac{1}{2} \times Area$

$\sqrt{3} \dfrac{i^2}{4} = \dfrac{1}{2} \times 4\sqrt{3}$

$\dfrac{i^2}{4} = \dfrac{1}{2} \times 4$

$\dfrac{i^2}{4} =2$

$i^2 = 8$

$i= \sqrt{8}$

$i= \sqrt{4 \times 2}$

$i= 2 \sqrt{2}$

Finally, the new height of the new triangle is:

$IL =\sqrt{3} \dfrac{i}{2}$

$IL =\sqrt{3} \dfrac{2 \sqrt{2}}{2}$

$IL =\sqrt{3 \times 2}$

$IL =\sqrt{6}$

IL = 2.449 m

6 0

4 years ago

photoshop1234 [79]

Answer:

10

Step-by-step explanation:

5/x = 4/8

Cross multiply

4*x = 5*8

4x = 40

x = 10

Answer is 10

You are correct

3 0

3 years ago