Answer:
Lisa will not be able to feed both tanks the same amount of food.
Step-by-step explanation:
This question is incomplete, here is the complete question :
"Lisa pet shop has 2 fish tank . Tank A contains smaller fish who were fed 1 gram of food each per day. Tank B contains larger fish who are fed 2 gram each per day. If tank B contains 2/3 the number of fish Tank A contains,will Lisa ever feed both tanks the same amount of food."
Let the number of fish in tank A = f
Lisa fed 1 gram of food each per day = f × 1 = f
So,the number of fish in tank B = 
Lisa fed 2 gram of food each per day = 
If both the tanks are fed with same amount of food then


⇒ 3f = 4f
⇒ 3 = 4
But 3 ≠ 4
Therefore, Lisa will not be able to feed both tanks the same amount of food.
Answer:
x = -1/2.
Step-by-step explanation:
x^2 - 4 = (x - 2)(x + 2) so if we multiply each term by x^2 -4 we get:
2 - 1(x - 2) = 3(x + 2)
2 - x + 2 = 3x + 6
2 + 2 - 6 = 3x + x
4x = -2
x = -1/2.
Answer: is y=7/3x+4
Step-by-step explanation:
1) add twelve to both sides- this will cancel out the 12
2)you now have 7x+12=3y
3) divide three on both sides. note you put everything over three on the left
4) 7 over 3 (x)+4=y is what you get when you finish doing the simple computations
5) flip the whole thing around so it fits the form. remember that addition can be anywhere as long as you don't switch sides of the equation
you will get: y=7/3x+4
1.6 & 3.784 hope this helped