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dimaraw [331]
3 years ago
12

Tickets for a minor league baseball game for an adult and two children cost a total of $21 the adult ticket is three dollars mor

e than a child's ticket. Find the cost of the child's ticket and an adult ticket.
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:the cost of one child's ticket is $6

the cost of one adult ticket is $9

Step-by-step explanation:

Let x represent the cost of one child's ticket

Let y represent the cost of one adult ticket.

Tickets for a minor league baseball game for an adult and two children cost a total of $21. This means that

2x + y = 21 - - - - - - - - - - 1

The adult ticket is three dollars more than a child's ticket. This means that

y = x + 3

Substituting y = x + 3 into equation 1, it becomes

2x + x + 3 = 21

3x + 3 = 21

3x = 21 - 3 = 18

x = 18/3 = 6

y = x + 3 = 6 + 3

y = 9

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shusha [124]
There are two triangles that are 15cm in height and 10cm in width so you do 15 times 10 which is 150 then divided it by 2 because it a triangle to get 75 then because there is 2 you then multiply it by 2 again and you get 150
3 0
3 years ago
Given: ∆AKM, R = 2, m∠A = 33°, O∈ AM . Find: perimeter of ∆AKM
Gwar [14]

Answer:

∆AKM is a right triangle for it is inscribed in semicircle O.

AM = diameter of semi-circle O = 2R = 2(2) = 4

%22AK%22%2F%22AM%22=cos%2833%5Eo%29

AK+=+AM%2Acos%2833%5Eo%29

AK+=+4cos%2833%5Eo%29

%22KM%22%2F%22AM%22=sin%2833%5Eo%29

KM+=+AM%2Asin%2833%5Eo%29

KM+=+4sin%2833%5Eo%29

The perimeter of a triangle is the sum of the three sides.

perimeter=AK%2BKM%2BAM

perimeter=4cos%2833%5Eo%29%2B4sin%2833%5Eo%29%2B4

Approximately 9.533238412

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the value of log Subscript 6 Baseline StartFraction 1 Over 36 EndFraction?
loris [4]

Answer:

-2

Step-by-step explanation:

Let  x be the unknown value  

Log₆  ( 1/36) = x

( 1/36) = 36⁻¹ = (6²)⁻¹ = 6⁻²

Log₆  ( 1/36) = Log₆ 6⁻²  = -2 Log₆ 6

Log₆ 6 = 1

-2 Log₆ 6 = -2(1) = -2

4 0
3 years ago
Read 2 more answers
Suppose a research firm conducted a survey to determine the average amount of money steady smokers spend on cigarettes during a
olchik [2.2K]

Answer:

option (b) 0.0228

Step-by-step explanation:

Data provided in the question:

Sample size, n = 100

Sample mean, μ = $20

Standard deviation, s = $5

Confidence interval = between $19 and $21

Now,

Confidence interval = μ ± z\frac{s}{\sqrt n}

thus,

Upper limit of the Confidence interval = μ + z\frac{s}{\sqrt n}

or

$21 =  $20 + z\frac{5}{\sqrt{100}}

or

z = 2

Now,

P(z = 2) = 0.02275                       [From standard z vs p value table]

or

P(z = 2) ≈ 0.0228

Hence,

the correct answer is option (b) 0.0228

3 0
3 years ago
Yesterday, stanley's doughnut shop sold 2/3 as many chocolate doughnuts as cinnamon doughnuts. if they sold 7 1/4 trays of cinna
katovenus [111]
You figure out the amount of chocolate doughnuts sold by multiplying 2/3 by 7 1/4

first you change 7 1/4 to an improper fraction:
7 1/4= 29/4
now multiply 2/3×29/4 by multiplying the two numerators then putting that over the two denominators multiplied: (2×29)/(3×4)=58/12
now simplify:58/12=4 10/12= 4 5/6

the answer is Stanley's doughnut shop sold
4 5/6 trays of chocolate doughnuts
5 0
3 years ago
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