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dimaraw [331]
3 years ago
12

Tickets for a minor league baseball game for an adult and two children cost a total of $21 the adult ticket is three dollars mor

e than a child's ticket. Find the cost of the child's ticket and an adult ticket.
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:the cost of one child's ticket is $6

the cost of one adult ticket is $9

Step-by-step explanation:

Let x represent the cost of one child's ticket

Let y represent the cost of one adult ticket.

Tickets for a minor league baseball game for an adult and two children cost a total of $21. This means that

2x + y = 21 - - - - - - - - - - 1

The adult ticket is three dollars more than a child's ticket. This means that

y = x + 3

Substituting y = x + 3 into equation 1, it becomes

2x + x + 3 = 21

3x + 3 = 21

3x = 21 - 3 = 18

x = 18/3 = 6

y = x + 3 = 6 + 3

y = 9

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Nady [450]

Answer:

2

Step-by-step explanation:

The GCF of 10 and 46 is 2. I hope this helps.

6 0
3 years ago
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If two angles are complementary each angle is called a complement of the other if two angles are supplementary each angle is cal
professor190 [17]
Remember that complementary angles add to 90 degrees.

so therefor, you can find the complement of m<A by solving 

90 - 77 = A

A = 13 degrees

^^^ This explains the second part.

The compliment of a compliment can be found by subtracting the known compliment from 90 :) 
8 0
3 years ago
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For her exercise today, Keiko plans to both run and swim. Let r be the number of laps she runs and let s be the number of laps s
DerKrebs [107]

Answer:

5r + 3s ≥ 30

Step-by-step explanation:

We know Keiko wants to do exercise at least 30 minutes a day, and she wants ideally to mix up the activities, by combining running and swimming into her schedule.

Since each lap she runs takes 5 minutes and each lap she swims takes 3 minutes, these will be the left side of the inequality:

5r + 3s

She wants to exercise at least 30 minutes a day, so...

5r + 3s ≥ 30

she could do 3 laps of running and 5 laps of swimming for example.

6 0
3 years ago
Please solve 108 = 2X-4(2X-9)
Fynjy0 [20]
108=2x-4(2x-9)
108=2x-8x+36
108=-6x+36
-36         -36
72=-6x
72/-6=-6x/-6
-12=x
3 0
3 years ago
If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

4 0
3 years ago
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