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Andrew [12]
4 years ago
8

When the pumpkin is shot straight upward with an initial speed of 14 m/s , what is the maximum height above its initial equation

Physics
1 answer:
Dmitrij [34]4 years ago
8 0

Answer:

10 m

Explanation:

At the maximum height, the velocity is 0.

Given:

v₀ = 14 m/s

v = 0 m/s

a = -9.8 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s)² = (14 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 10 m

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When a 2.50 kg object is hung vertically on a certain light spring described by hookes law the spring stretches 2.76 cm.
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4 years ago
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SVETLANKA909090 [29]

<u>Answer:</u>

1) Distance traveled by bird = 403 meter

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3)    Acceleration is defined as the rate of change of velocity, so acceleration a = change in velocity/time.

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