A badger is running at a speed of 1 m/s. If the badger moves that was for 2600 seconds, how far will the badger travel?
1 answer:
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Hello there.
1.986*1,000,000
<u><em>Answer=1,986,000</em></u>
Explanation: First you had to ten to the six power of the ten with six times. It gave us 1000000 should be have six zeros at any time. Then you can multiply by 1.986*1000000=1,986,000 is the right answer. Hope this helps! Thank you for posting your question at here on Brainly. -Charlie
Answer:
A
B
Explanation:
From the question we are told that
The wavelength is
The angle of first bright fringe is
The order of the fringe considered is n =1
Generally the condition for constructive interference is
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Converting to cm
Generally the number of grating pre centimeter is mathematically represented as
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Considering question B
From the question we are told that
The first wavelength is
The second wavelength is
The order of the fringe is
The grating is
Generally the slit width is mathematically represented as
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=>
Generally the condition for constructive interference for the first ray is mathematically represented as
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=>
=>
Generally the condition for constructive interference for the second ray is mathematically represented as
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Generally the angular separation is mathematically represented as
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