Answer:
<h2>3.6°</h2>
Step-by-step explanation:
The question is incomplete. Here is the complete question.
Find the angle between the given vectors to the nearest tenth of a degree.
u = <8, 7>, v = <9, 7>
we will be using the formula below to calculate the angle between the two vectors;

is the angle between the two vectors.
u = 8i + 7j and v = 9i+7j
u*v = (8i + 7j )*(9i + 7j )
u*v = 8(9) + 7(7)
u*v = 72+49
u*v = 121
|u| = √8²+7²
|u| = √64+49
|u| = √113
|v| = √9²+7²
|v| = √81+49
|v| = √130
Substituting the values into the formula;
121= √113*√130 cos θ
cos θ = 121/121.20
cos θ = 0.998
θ = cos⁻¹0.998
θ = 3.6° (to nearest tenth)
Hence, the angle between the given vectors is 3.6°
Answer:
V=56
Step-by-step explanation:
times both sides by 7
Answer: 33 square units
Step-by-step explanation:
Given: Sides lengths of the triangle : 16 units, 10 units, 8 units.
Heron's formula:-
, where s is the semiperter and a,b and c are the side-lengths of the triangle.
Let a=16 , b=10 and c=8
Then,

Using Heron's formula:-

Its the second option!
The range expresses the constraints of y-values of a function. There is a solid point at positive three which means that it is included. The open point at -3 means it’s not included. This makes the range -3