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BARSIC [14]
3 years ago
9

Pls send answer and show work pls

Mathematics
1 answer:
I am Lyosha [343]3 years ago
4 0
For question 7, if we add all votes for tiger and eagle, we get

tiger = 14 + 13 + 8 + 5 = 40
eagle = 6 + 7 + 12 + 15 = 40

so choices A and B are wrong.
C is also wrong because fifth and sixth grade votes for eagle are 6 + 7 = 13 and the 5th and 6th grade votes for tiger are 14 + 13 = 27. clearly 5th + 6th like tiger more.

D is the answer for question 7

question 8

rolling a cube does not affect the other cube so it is all independent probability.
cube: 1 2 3 4 5 6
3 even numbers and 3 odd numbers

so probability of rolling an even number is

1/6 + 1/6 + 1/6 = 3/6 = 1/2

multiplying by total number of rolls, she will get even numberss

300 * 1/2 = 150

about 150 time.
so half of the time, Cassie will roll and even number about half the number of rolls. never exactly since this is all probability. more likely for it to be around 150 times than exactly 150 time.

choice C is answer for question 8
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Step-by-step explanation:

The way you get the area of a parellelogram is the same as the way of a rectangle or square.

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The fish population in a certain lake rises and falls according to the formula F = 3000(23 + 11t − t2). Here F is the number of
Gemiola [76]

Answer:

a) On January 1, 2017 the fish population will be the same as the initial population.

b) On September 18th, 2018 the fish population will be zero.

Step-by-step explanation:

Hi there!

a) First, let´s write the function:

F(t) = 3000(23 + 11t − t²)

The population on January 1, 2006 is the population at t = 0. Then:

F(0) = 3000(23 + 11· 0 - 0²)

F(0) = 3000 · 23 = 69000

This will be the population every time at which t² - 11t = 0. Then let´s find the other value of t (besides t = 0) that makes that expression to be zero:

t² - 11t = 0

t(t - 11) = 0

t = 0

and

t - 11 = 0

t = 11

On January 1, 2017 (2006 + 11), the fish population will be the same as the initial population.

b) We have to obtain the value of t at which F(t) = 0

F(t) = 3000(23 + 11t − t²)

0 = 3000(23 + 11t − t²)

divide both sides of the equation by 3000

0 = 23 + 11t − t²

Let´s solve this quadratic equation using the quadratic formula:

a = -1

b = 11

c = 23

x = [-b ± √(b² - 4ac)] / 2a

x = 12.8  ( the other value of x is negative and therefore discarded).

After 12.8 years all the fish in the lake will have died.

If 1 year is 12 months, 0.8 years will be:

0.8 years · 12 months/year = 9.6 months

If 1 month is 30 days, 0.6 month will be:

0.6 month · 30 days / month = 18 days

All the fish will have died after 12 years, 9 months and 18 days from January 1, 2006. That is, on September 18th, 2018.

7 0
3 years ago
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