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sineoko [7]
3 years ago
15

Which of the following is a physical property of a substance?? A. Combustion B. Corrosion C. Tendency to tarnish D. Solubility

Chemistry
2 answers:
Fofino [41]3 years ago
6 0
A physical property does not change the substance. 

Solubility would be the answer since all of the rest are changing the substance. They all deal with bonds except solubility. 

Answer: D. Solubility

Vinvika [58]3 years ago
5 0
<span>A physical property is any property that does not concern with the change of the substance. The changes in the physical property can be used to describe its transformations or evolutions from its initial state. They are often referred to as observables. Solubility is an example of a physical property. The solubility of substance describes a state of a dissolving a powdered form in a liquid. Combustion, Corrosion and tendency to tarnish are examples of a chemical change. They are substances that changes its physical state and composition resulting from a chemical reaction</span>
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3 years ago
What do the elements in each pair have in common? k, kr be, mg ni, tc b, ge al, pb?
tensa zangetsu [6.8K]
The pairs are:
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Be, Mg - Same group
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4 0
3 years ago
Which of the following has a mass of 10.0 g?
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Answer:

a.  0.119mol Kr

Explanation:

To solve this problem, we must understand that;

     Mass  = number of moles x molar mass

Molar mass of Kr  = 83.3g/mol

                        Ar = 40g/mol

                        He = 4g/mol

                        Ne = 20.18g/mol

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b 0.400 mol Ar             mass  = 0.4 x 40  = 16g

C 1.25 mol He               mass  = 1.25 x 4  = 5g

d 2.02 mol Ne              mass  = 2.02 x 20.18  = 40.8

Krypton is the answer

5 0
3 years ago
If 9.85 grams of copper metal react with 31.0 grams of silver nitrate, how many grams of copper nitrate can be formed and how ma
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<span>Cu + 2AgNO3 = Cu(NO3)2 + 2Ag
</span>
We are given the amount of the reactants to be used for the reaction. These values will be the starting point of our calculations.

9.85 g Cu ( 1 mol Cu / 63.55 g Cu ) = 0.15 mol Cu
31.0 g AgNO3 ( 1 mol AgNO3 / 169.87 g AgNO3 ) = 0.18 mol AgNO3

The limiting reactant is AgNO3.

0.18 mol AgNO3 ( 1 mol Cu(NO3)2 / 2 mol AgNO3 ) (187.56 g / 1 mol) =16.88 g Cu(NO3)2

0.15 mol Cu - 0.18 mol AgNO3 ( 1 mol Cu / 2 mol AgNo3) = 0.06 mol Cu excess

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3 0
3 years ago
Read 2 more answers
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