CS2 + 3O2 = CO2 + 2SO2
1 mole of CS2 gives 1 mole of CO2
12 + 2(32) = 76g of CS2 yields 44 g of CO2
Theoretically 1 g of CS2 yields 44/76 g CO2
Therefore 50 g CS2 should yield 50*44 / 76 = 28.95 g
So % yield = 103.6 % ( which is not possible because you can't create matter from nothing).
The 30g cannot be right . This is experimental err.
Answer:
The factor of increasing reaction rate is 1,85x10¹².
Explanation:
Using arrhenius formula:

Where k is rate constant; A is frecuency factor; Eₐ is activation energy; R is gas constant (0,008134 kJ/molK); T is temperature 25°C = 298,15K
Thus, replacing for an activation energy of 125 kJ/mol assuming A as 1:
k = 1,25x10⁻²²
When activation energy is 55kJ/mol:
k = 2,31x10⁻¹⁰
Thus, the factor of increasing reaction rate is:
2,31x10⁻¹⁰/1,25x10⁻²² =<em> 1,85x10¹²</em>
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I hope it helps!
Answer:
The answer would either be Carbon or Silicon.
Explanation:
Answer:
36.51%.
Explanation:
First find the percentage of iron in pure Fe2O3 using the atomic masses of the elements:
= (2 * 55.845) * 100 / (2*55.845+ 3*15.999)
= 69.94 %.
So the percentage of iron in the mixture
= 52.2 * 0.6994
= 36.51 (answer).
I want to say 8 but i'm not sure. I just did a lesson on this and my notes say it could be 8 but then again I'm not sure.