Answer:
(4,20)
Explanation:
Oxygen di-fluoride or OF2 is a polar molecule, formed through the covalent bonding between one Oxygen and two Fluorine atoms.
Oxygen has atomic no. 8 and its electronic configuration is as below:
Oxygen has 4 electrons in the valence shell. It has the ability to share two electrons with other atoms through covalent bond and get stable.
The atomic number of Fluorine is 7, and its electronic configuration is as:
So, Fluorine atom has the capacity to accept 1 electron to form 1 covalent bond or in the formation of the F- ion.
The structure of OF2 is a bent structure with O atom sandwiched by two fluorine atoms like F-O-F. So there are two electrons on oxygen atom that are taking part in the formation of covalent bond with each Fluorine atom (Please dot structure in figure).
Now we can easily calculate no of bonding and non-bonding electrons.
- No. of bonding electrons = 4 (two from oxygen and two from fluorine atoms each)
- No. of non-bonding electrons= 20 (6+6 from two Fluorine atoms and 6 from Oxygen atom)
Hope it helps! :)
Answer: Nucleus of an atom is heavy and positively charged because nucleus is only made up of protons and neutrons.
The
combustion of heptane (C7H16) in oxygen spontaneously occurs. The products of
the reaction are carbon dioxide and water vapor. The balanced chemical equation
is 7H16 + 11O2 → 7CO2 + 8H2O H
= –2877.5 kJ.
Answer:- As per the question is asked, 35.0 moles of acetylene gives 70 moles of carbon dioxide but if we solve the problem using the limiting reactant which is oxygen then 67.2 moles of carbon dioxide will form.
Solution:- The balanced equation for the combustion of acetylene is:
From the balanced equation, two moles of acetylene gives four moles of carbon dioxide. Using dimensional analysis we could show the calculations for the formation of carbon dioxide by the combustion of 35.0 moles of acetylene.
= 
The next part is, how we choose 35.0 moles of acetylene and not 84.0 moles of oxygen.
From balanced equation, there is 2:5 mol ratio between acetylene and oxygen. Let's calculate the moles of oxygen required to react completely with 35.0 moles of acetylene.
= 
Calculations shows that 87.5 moles of oxygen are required to react completely with 35.0 moles of acetylene. Since only 84.0 moles of oxygen are available, the limiting reactant is oxygen, so 35.0 moles of acetylene will not react completely as it is excess reactant.
So, the theoretical yield should be calculated using 84.0 moles of oxygen as:
= 
