Answer: The concentrations of
at equilibrium is 0.023 M
Explanation:
Moles of
= ![\frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bgiven%20mass%7D%7D%7B%5Ctext%20%7BMolar%20mass%7D%7D%3D%5Cfrac%7B10g%7D%7B71g%2Fmol%7D%3D0.14mol)
Volume of solution = 1 L
Initial concentration of
= ![\frac{0.14mol}{1L}=0.14M](https://tex.z-dn.net/?f=%5Cfrac%7B0.14mol%7D%7B1L%7D%3D0.14M)
The given balanced equilibrium reaction is,
![COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)](https://tex.z-dn.net/?f=COCl_2%28g%29%5Crightleftharpoons%20CO%28g%29%2BCl_2%28g%29)
Initial conc. 0.14 M 0 M 0M
At eqm. conc. (0.14-x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5Ctimes%20%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
Now put all the given values in this expression, we get :
![4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}](https://tex.z-dn.net/?f=4.63%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7Bx%29%5E2%7D%7B%280.14-x%29%7D)
By solving the term 'x', we get :
x = 0.023 M
Thus, the concentrations of
at equilibrium is 0.023 M
Answer : The energy of the photon emitted is, -12.1 eV
Explanation :
First we have to calculate the
orbit of hydrogen atom.
Formula used :
![E_n=-13.6\times \frac{Z^2}{n^2}ev](https://tex.z-dn.net/?f=E_n%3D-13.6%5Ctimes%20%5Cfrac%7BZ%5E2%7D%7Bn%5E2%7Dev)
where,
= energy of
orbit
n = number of orbit
Z = atomic number of hydrogen atom = 1
Energy of n = 1 in an hydrogen atom:
![E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV](https://tex.z-dn.net/?f=E_1%3D-13.6%5Ctimes%20%5Cfrac%7B1%5E2%7D%7B1%5E2%7DeV%3D-13.6eV)
Energy of n = 2 in an hydrogen atom:
![E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV](https://tex.z-dn.net/?f=E_3%3D-13.6%5Ctimes%20%5Cfrac%7B1%5E2%7D%7B3%5E2%7DeV%3D-1.51eV)
Energy change transition from n = 1 to n = 3 occurs.
Let energy change be E.
![E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV](https://tex.z-dn.net/?f=E%3DE_-E_3%3D%28-13.6eV%29-%28-1.51eV%29%3D-12.1eV)
The negative sign indicates that energy of the photon emitted.
Thus, the energy of the photon emitted is, -12.1 eV
Answer: because it consists of more than one element, which are hydrogen and oxygen in a covalent bond.
The postulate of Dalton's atomic theory which is a result of the law of conservation of mass is: Atoms are indivisible particles, which can neither be created nor destroyed in a chemical reaction.