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velikii [3]
3 years ago
10

Answer the following question: Ethanol, C2H5OH, is considered clean fuel because it burns in oxygen to produce carbon dioxide an

d water with few trace pollutants. If 325.0 g of H2O are produced during the combustion of ethanol, how many grams of ethanol were present at the beginning of the reaction? When answering this question include the following: Have both the unbalanced and balanced chemical equations. Explain how to find the molar mass of the compounds. Explain how the balanced chemical equation is used to find the ratio of moles (hint: step 3 in the video). Explain how many significant figures your answer needs to have. The numerical answer
Chemistry
1 answer:
musickatia [10]3 years ago
3 0
127.88 grams of ethanol were present at the beginning of the reaction
Explanation:
Firstly, let's make the combustion reaction:
C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
By 1 mol of ethanol, you can make 3 mole of water.
Mole of water = Water mass / Molar mass
150g / 18g/m = 8.3 mole
3 mole of water came from 1 mol of ethanol
8.3 mole came from (8.3 .1)/3 = 2.78 mole of ethanol
Molar mass ethanol = 46 g/m
Mole . molar mass = mass
2.78 m . 46g/m = 127.88 g
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What is the driving force of convection in the atmosphere and ocean?
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<span>Mantle convection is the slow creeping motion of Earth's rocky mantle caused by convection currents carrying heat from the interior of the earth to the surface. It is one of 3 driving forces that causes tectonic plates to move around the Earth's surface.</span>
7 0
3 years ago
The heating curve for a sample of pure ethanol shows the slope of the line for gaseous state is greater than the slope of the li
Agata [3.3K]

Answer:

a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.

Explanation:

The heating curve is a curve that represents temperature (T) in the y-axis vs. added heat (Q) in the x-axis. The slope is T/Q = 1/C, where C is the heat capacity. Then, the higher the slope, the lower the heat capacity. For a constant mass, it can also represent the specific heat capacity (c).

Heats of vaporization and fusion cannot be calculated from these sections of the heating curve.

<em>Which statement below explains that?</em>

<em>a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.</em> YES.

<em>b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol.</em> NO.

<em>c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol.</em> NO.

<em>d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol.</em> NO.

3 0
3 years ago
What is the electric force on a proton 2.5 fmfm from the surface of the nucleus? Hint: Treat the spherical nucleus as a point ch
sammy [17]

Explanation:

It is known that charge on xenon nucleus is q_{1} equal to +54e. And, charge on the proton is q_{2} equal to +e. So, radius of the nucleus is as follows.

            r = \frac{6.0}{2}

              = 3.0 fm

Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.

              d = r + 2.5

                 = (3.0 + 2.5) fm

                 = 5.5 fm

                 = 5.5 \times 10^{-15} m     (as 1 fm = 10^{-15})

Therefore, electrostatic repulsive force on proton is calculated as follows.

              F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

Putting the given values into the above formula as follows.

           F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

              = (9 \times 10^{9}) \frac{54e \times e}{(5.5 \times 10^{-15})^{2}}

              = (9 \times 10^{9}) \frac{54 \times (1.6 \times 10^{-19})^{2}}{(5.5 \times 10^{-15})^{2}}

              = 411.2 N

or,           = 4.1 \times 10^{2} N

Thus, we ca conclude that 4.1 \times 10^{2} N is the electric force on a proton 2.5 fm from the surface of the nucleus.

8 0
4 years ago
Standard reduction potentials are 1.455 V for the PbO2(s)/Pb(s) couple, 1.82 V for Co3 (aq)/Co2 (aq), 3.06 V for F2(g)/HF(aq), 1
zavuch27 [327]

Answer:

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Explanation:

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This implies that we could know a good oxidizing agent by looking at their respective reduction potentials. The couple having the greatest (most positive) reduction potential is selected as the best oxidizing agent. If there are a number of couples at having different reduction potentials, the order of oxidizing ability can be obtained by arranging the species in order of decreasing positive reduction potentials just as we have done in the answer above.

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3 years ago
A real gas behaves more like an ideal gas when the gas molecules are
Vitek1552 [10]
Far apart and have weak attractive forces between them
7 0
3 years ago
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