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Alex73 [517]
3 years ago
10

28 grams of Al react with 30 Oxygen gas (O2) to produce Al Oxide (Al2O3). How many grams of Al Oxide will be produced

Chemistry
1 answer:
Kamila [148]3 years ago
8 0

Answer:

58

Explanation:

Due to conservation of energy, the sum of the reactants = the sum of the products. So 28 + 30 = 58g

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Answer:

a) Cl_2 + 3F_2 \rightarrow 2ClF_3

b) F_2 is the limiting reagent

c) Moles of ClF_3 produced = 2.45 mol

b) Moles of Cl_2 left = 1.75 -1.22 = 0.53

Explanation:

a) Balanced reaction:

Cl_2 + 3F_2 \rightarrow 2ClF_3

b)

No. of mole of Cl_2 = 1.75\ mol

No. of mole of F_2 = 3.68\ mol

Cl_2 + 3F_2 \rightarrow 2ClF_3

As, it is clear from the reaction that,

1 mol of Cl_2 requires 3 moles of F_2

1.75 mol of Cl_2 require = 1.75 × 3 = 5.25 mol of F_2

As, only 3.68 mol of F_2 is present, so F_2 is the limiting reagent.

c)

3 moles of F_2 form 2 moles of ClF_3

3.68 moles of F_2 will form = \frac{2}{3}  \times 3.68 = 2.45\ mol\ of\ ClF_3

d)

Cl_2 is present in excess.

3 moles of F_2 requires 1 mol of Cl_2

3.68 moles of F_2 will require = \frac{1}{3} \times 3.68 = 1.22\ mol\ of\ Cl_2

Cl_2 left = 1.75 -1.22 = 0.53 mol

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4 years ago
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The struggle among organism for food, water and other needs is called what
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Answer: C.)competition.

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Hello!

To find the mass in grams of 100 atoms of carbon, we need to use Avogadro's number, which is 6.02 x 10^23 grams, and divide that by the total number of atoms.

Next, we would need to find how much one mole of carbon weighs. In this case, it is exactly 12 grams.

1. Divide by Avogadro's number

100 / (6.02 x 10^23) ≈ 1.66 x 10^-22  

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