Fractional distillation
Explanation:
The best way to separate the mixtures out is through the process of fractional distillation.
In fractional distillation, liquid - liquid mixtures are separated based on the differences in boiling point of their components. Let us examine the boiling points of the component of the mixtures:
Ethanol 78⁰C
Glycerol 290⁰C
Ethylene glycol 197.6⁰C
Methanol 64.7⁰C
Water 100⁰C
We see that the liquids in the mixture have different boiling points. In this process, the mixture is heated in a distillation column. When the boiling point of any component is reached, it will rise up in the column and can be channeled to a condenser where it is cooled and collected.
The liquid with the least boiling point is first separated with the one with the highest boiling is recovered last:
Order of recovery;
Methanol 64.7⁰C
Ethanol 78⁰C
Water 100⁰C
Ethylene glycol 197.6⁰C
Glycerol 290⁰C
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Physical properties brainly.com/question/10972073
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Answer:
Whenever a force is applied to an object, causing the object to move, work is done by the force. ... Work can be either positive or negative: if the force has a component in the same direction as the displacement of the object, the force is doing positive work
2SO₂ + O₂ = 2SO₃
n(O₂)=1 mol
n(SO₂)=2n(O₂)
n(SO₂)=2 mol
Answer:
12.99
Explanation:
<em>A chemist dissolves 716. mg of pure potassium hydroxide in enough water to make up 130. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits.</em>
Step 1: Given data
- Mass of KOH: 716. mg (0.716 g)
- Volume of the solution: 130. mL (0.130 L)
Step 2: Calculate the moles corresponding to 0.716 g of KOH
The molar mass of KOH is 56.11 g/mol.
0.716 g × 1 mol/56.11 g = 0.0128 mol
Step 3: Calculate the molar concentration of KOH
[KOH] = 0.0128 mol/0.130 L = 0.0985 M
Step 4: Write the ionization reaction of KOH
KOH(aq) ⇒ K⁺(aq) + OH⁻(aq)
The molar ratio of KOH to OH⁻is 1:1. Then, [OH⁻] = 0.0985 M
Step 5: Calculate the pOH
We will use the following expression.
pOH = -log [OH⁻] = -log 0.0985 = 1.01
Step 6: Calculate the pH
We will use the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 -1.01 = 12.99
