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wariber [46]
3 years ago
12

Calculate the molarity of a solution prepared using 127 grams of KCI with a volume of 552 mL

Chemistry
1 answer:
den301095 [7]3 years ago
4 0

Answer:

mass of 1  mole of 127 grams, KCI, 552mL = 51.1099987g

Explanation:

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PLEASE HELPP!!!!
Natasha_Volkova [10]

Answer:

<em>The combined law is:</em>

          \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}

See the derivation below.

Explanation:

<em><u>1. Boyle's law:</u></em>

    PV=constant\\\\P_1V_1=P_2V_2

<em />

<u><em>2. Charles' law:</em></u>

        \dfrac{V}{T}=constant\\\\\\\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

<em><u>3. Gay-Lussac’s law</u></em>

      \dfrac{P}{T}=constant\\\\\\\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

<u>4. Summary:</u>

  •    PV = K
  •    V/T = K'
  •    P/T = K''

Mulitply PV by V/T and P/T

        PV\times \dfrac{V}{T}\times \dfrac{P}{T}=K\times K'\times K''\\\\\\\dfrac{P^2V^2}{T^2}=constant\\\\\\\sqrt{\dfrac{P^2V^2}{T^2}}=\sqrt{constant}\\\\\\\dfrac{PV}{T}=constant

Thus:

          \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}

Which is<em> the combined law.</em>

4 0
4 years ago
When a strip of magnesium metal is placed in an aqueous solution of copper(II) nitrate, elemental copper coats the surface of th
Lera25 [3.4K]

Answer:

1. 2+ (Cu^{2+}).

2. 0 (Cu^0).

Explanation:

Hello,

In this case, the described chemical reaction is a redox reaction in fact, since the oxidation states of both magnesium and copper change as shown due to the displacement:

Mg(s)+Cu(NO_3)_2(aq)\rightarrow Mg(NO_3)_2(aq)+Cu(s)

Therefore:

1. Since copper is the cation in the copper (II) nitrate, the (II) means that its charge is 2+ (Cu^{2+}).

2. Since copper is alone, it means no electrons are being neither shared not given, its charge is 0 (Cu^0).

Best regards.

4 0
3 years ago
Assuming ideal behavior, how many moles of argon would you need to fill a 14.0×12.0×10.0 ft room? assume atmospheric pressure of
UNO [17]

We use the formula:

PV = nRT

First let us get the volume V:

volume = 14 ft * 12 ft * 10 ft = 1,680 ft^3

Convert this to m^3:

volume = 1680 ft^3 * (1 m / 3.28 ft)^3 = 47.61 m^3

 

n = PV / RT

n = (1 atm) (47.61 m^3) / (293.15 K * 8.21x10^-5 m3 atm / mol K)

<span>n = 1,978.13 mol</span>

5 0
3 years ago
I’m so lost please help
Vadim26 [7]

d= 8/10 so yah that was a guess

8 0
3 years ago
When you blow up a balloon,
FromTheMoon [43]
The answer is B. Chemical change
4 0
3 years ago
Read 2 more answers
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