The system that shows a decrease in entropy (disorder) is

1 answer:

wel4 years ago

8 0

There is no definite definition of entropy. In books, entropy is usually introduced through differential equations relating enthalpy and Gibb's free energy. However, that is an advanced explanation. For simplicity, entropy is the state of disorder. So, when the system shows a decrease in entropy, the system's molecules gets in order. For example, freezing water puts it in order because liquid water molecules are compacted into solid crystals. In relation, for a decrease in entropy, the reaction is more non-spontaneous.

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How many molecules of sugar are there in 1 can of soda?

Korvikt [17]

Answer:

$5.8\cdot 10^{22}$

Explanation:

Since no information was provided about the can of soda, let's take an example of 1 can of 12 fl oz (368 g) Coca-Cola.

The nutrition facts state that it contains 33 g of sugar. In order to calculate the number of molecules, we firstly need to know the molecular formula of sugar. Sugar can be represented by $C_{12}H_{22}O_{11}$ .

Our first step is to find the molar mass of sugar:

$M_{C_{12}H_{22}O_{11}} = 342.3 g/mol$

Secondly, dividing mass of sugar, $m = 33 g$ , by the molar mass will yield the number of moles of sugar:

$n_{C_{12}H_{22}O_{11}}=\frac{m}{M}$

Finally, multiplying moles by the Avogadro's constant will yield the number of molecules:

$N_{C_{12}H_{22}O_{11}}=n_{C_{12}H_{22}O_{11}}\cdot N_A =\frac{m}{M} \cdot N_A = \frac{33 g}{342.3 g/mol} \cdot 6.022 \cdot 10^{23} mol^{-1} = 5.8\cdot 10^{22}$

8 0

4 years ago

blast furnaces give off many unpleasant and unhealthy gases. If the total air pressure is .99 ATM the partial pressure of carbon

kolbaska11 [484]

Answer:

$P_{air}=1.02atm$

Explanation:

Hello!

In this case, since the Dalton's law help us to realize that the total pressure of a gas mixture is computed by adding the partial pressure of each composing gas, for the mixture formed by carbon dioxide, oxygen sulfide (should be hydrogen sulfide instead) and air, we can write:

$P=P_{CO_2}+P_{H_2S}+P_{air}$

Thus, given the total pressure and the partial pressures of both carbon dioxide and hydrogen sulfide, the partial pressure of the remaining air would be:

$P_{air}=P_{T}-P_{H_2S}-P_{CO_2}$