The solution to your problem is as follows:
<span>2 KClO3 → 2 KCl + 3 O2
</span><span>MW of KCL = 39.1 + 35.35 = 74.6 g/mole
62.6/74.6 = 0.839 moles KCl produced
0.839 moles KCl x 3O2/2KCl x 32g/mole O2 = 40.27g of O2 was produced
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Therefore, there are <span>40.27g of O2 produced during the reaction.
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The answer you're looking for is B. The bond will be ionic.
Answer: The answer is 167
Explanation: This is because that was right on edg. so yea heart this tho plsss
Answer:
The answer to your question is 75%
Explanation:
Data
Theoretical production = 4 moles
Experimental production = 3 moles
Percent yield = ?
Formula

Substitution

Result
Percent yield = 75 %
Answer:
the answer to the qustion is 0.013089701 na
Explanation:
n/a