Given that solubility product of AgCl = 1.8 X 10^-10
Dissociation of AgCl can be represented as follows,
AgCl(s) ↔ Ag+(ag) + Cl-(aq)
Let, [Ag+] = [Cl-] = S
∴Ksp = [Ag+][Cl-] = S^2
∴ S = √Ksp = √(1.8 X 10^-10) = 1.34 x 10^-5 mol/dm3
Now, Molarity of solution =
∴ 1.34 x 10^-5 =
∴ Weight of AgCl present in solution = 1.92 X 10^-3 g
Thus,
mass of AgCl that will dissolve in 1l water = 1.92 x 10^-3 g
7.20594 x 10^20
First you must determine how many moles of P3O5 you have. This is done by using the formula
Number of moles (n) = mass in grams of substance (m) /divided by/ Molar mass (M) [this is the sum of the atomic mass of all atoms in the compound]
n = 0.170 / P (31 x 2) + O (16 x 5)
n = 0.170 / 142
n = 0.001197 moles
Then you use avagadros number 6.02 x10^23 this is the number of atoms in one mole of any substance. Since you have 0.001197 moles you multiply the number of moles by avagadros number
0.001197 x (6.02 x 10^23)
= 7.20594 x 10^20 atoms
D. Making the reactant particles larger
<u>Answer:</u> The energy released in the given nuclear reaction is 94.99 MeV.
<u>Explanation:</u>
For the given nuclear reaction:
We are given:
Mass of 
= 235.043924 u
Mass of 
= 1.008665 u
Mass of 
= 130.9061246 u
Mass of 
= 88.9058483 u u
To calculate the mass defect, we use the equation:
Putting values in above equation, we get:
To calculate the energy released, we use the equation:
(Conversion factor: 
)
Hence, the energy released in the given nuclear reaction is 94.99 MeV.
Answer:
(1s)^2 (2s)^2 (2p)^3
Explanation:
Nitrogen has 7 electrons. Hence, the structure will be,
=>(1s)^2 (2s)^2 (2p)^3
Hope it helps:)
