Moles=mass/Mr
mass=454
Mr=12+16+16=44
So,454/44=10.31mol
Answer is:10.31mol
835 g Ar to liters of Argon gas is calculated as follows
find the moles of Ar = mass/molar mass
= 835g /39.95 g/mol = 20.9 moles
At STP 1mole of ideal gas = 22.4 L, what about 20.9 moles
= 20.9 moles/1mole x 22.4 L =468.16 L of Argon
The entire mass of a black hole
Answer:
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