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3 years ago

What does " a man's home is his castle " mean

Chemistry

1 answer:

slega [8]3 years ago

8 0

It means that someone's home is more than just a home to someone much more meaningful and precious like a castle

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Which is a physical property of milk?

inna [77]

C) Milk boils at about 212°F (100°C).

6 0

3 years ago

Mass

DiKsa [7]

The molecular formula =C₆H₁₂O₆

<h3>Further explanation</h3>

Given

6.00 g of a certain compound X

The molecular molar mass of 180. g/mol

CO₂=8.8 g

H₂O=3.6 g

Required

The molecular formula

Solution

mass C in CO₂ :

= 1.12/44 x 8.8

= 2.4 g

mass H in H₂O :

= 2.1/18 x 3.6

= 0.4 g

Mass O in compound :

= 6-(2.4+0.4)

= 3.2 g

Mol ratio C : H : O

= 2.4/12 : 0.4/1 : 3.2/16

= 0.2 : 0.4 : 0.2

= 1 : 2 : 1

The empirical formula : CH₂O

(CH₂O)n=180 g/mol

(12+2+16)n=180

(30)n=180

n=6

(CH₂O)₆=C₆H₁₂O₆

7 0

3 years ago

How fast must a 56.5-g tennis ball travel in order to have a de Broglie wavelength that is equal to that of a photon of green li

nikklg [1K]

Answer:vv

$v=2.17\times 10^{-26}\ m/s$

Explanation:

The expression for the deBroglie wavelength is:

$\lambda=\frac {h}{m\times v}$

Where,

$\lambda$ is the deBroglie wavelength

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

m is the mass of = $56.5\ g=0.0565\ kg$

v is the speed.

Wavelength = 5400 Å = $5400\times 10^{-10}\ m$

Applying in the equation as:-

$5400\times 10^{-10}=\frac{6.626\times 10^{-34}}{0.0565\times v}$

$v=\frac{331300000}{10^{34}\times \:1.5255}\ m/s$

$v=2.17\times 10^{-26}\ m/s$

7 0

3 years ago

The equation shows lead reacting with sulfuric acid to produce lead sulfate and hydrogen gas. mc012-1.jpg Which type of chemical

krok68 [10]

Single replacement and I know that for sure if you need me to explain i can but its Single replacement <span />

4 0

3 years ago

Read 2 more answers

Calculate the OH− concentration after 53 mL of the 0.100 M KOH has been added to 25.0 mL of 0.200 M HBr. Assume additive vol- um

Andre45 [30]

Answer:

$\large \boxed{\text{0.0038 mol/L}}$

Explanation:

1. Calculate the initial moles of acid and base

$\text{moles of acid} = \text{0.0250 L} \times \dfrac{\text{0.200 mol}}{\text{1 L}} = \text{0.005 00 mol}\\\\\text{moles of base} = \text{0.053 L} \times \dfrac{\text{0.100 mol}}{\text{1 L}} = \text{0.0053 mol}$

2. Calculate the moles remaining after the reaction

OH⁻ + H₃O⁺ ⟶ 2H₂O

I/mol: 0.0053 0.005 00

C/mol: -0.00500 -0.005 00

E/mol: 0.0003 0

We have an excess of 0.0003 mol of base.

3. Calculate the concentration of OH⁻

Total volume = 53 mL + 25.0 mL = 78 mL = 0.078 L

$\text{[OH}^{-}] = \dfrac{\text{0.0003 mol}}{\text{0.078 L}} = \textbf{0.0038 mol/L}\\\\\text{The final concentration of OH$^{-}$ is $\large \boxed{\textbf{0.0038 mol/L}}$}$

8 0

3 years ago