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3 years ago

Which equation finds the area of a square with a side length of 5 n Superscript 4 units?

Mathematics

2 answers:

aleksandr82 [10.1K]3 years ago

5 0

A is the correct answer

I just took the quiz on edge

Oduvanchick [21]3 years ago

4 0

Answer:

area of a square is S^2

s = 5n^4

area = (5n^4)^2 = 25n^8

Step-by-step explanation:

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Grains of sand are very small, there being about 3000 grains in one cubic centimeter (cm3) of sand. A cm3 is a small cube measur

Anastasy [175]

Answer:

The value is $x = 3.000 * 10^9 \ grains$

Step-by-step explanation:

From the question we are told that

$1m^3 = 10^6 cm^3$

And that

$3000 \ grains \ of \ sand \ is \ in \ 1cm^3$

So the number of sand grain that is in $1m^3$ is mathematically evaluated as

$x = 3000 * 10^6 \ grains$

=> $x = 3.000 * 10^9 \ grains$

4 0

3 years ago

if emma spent $14.00 on jewerly and recieved $6.00 in change how much money did she spent . what equation could be used to find

rjkz [21]

14.00-6.00=8.00 if the cashier gave her 6.00 then she spent at least 8.00

7 0

3 years ago

Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125

liq [111]

For the given equation;

$(3x-5)^2=-125$

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

$\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}$

Now that we have expanded the left side of the equation, we would have;

$\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}$

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

$\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}$

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