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faltersainse [42]
3 years ago
15

Which equation finds the area of a square with a side length of 5 n Superscript 4 units?

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
5 0

A is the correct answer

I just took the quiz on edge

Oduvanchick [21]3 years ago
4 0

Answer:

area of a square is S^2

s = 5n^4

area = (5n^4)^2 = 25n^8

Step-by-step explanation:

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Grains of sand are very small, there being about 3000 grains in one cubic centimeter (cm3) of sand. A cm3 is a small cube measur
Anastasy [175]

Answer:

The value is x =  3.000 * 10^9 \  grains

Step-by-step explanation:

From the question we are told that

      1m^3 = 10^6 cm^3

And that

     3000 \  grains \ of \  sand  \  is  \ in \  1cm^3

So the number of sand grain that is in 1m^3 is mathematically evaluated as

      x =  3000 * 10^6 \  grains

=>  x =  3.000 * 10^9 \  grains

4 0
3 years ago
if emma spent $14.00 on jewerly and recieved $6.00 in change how much money did she spent . what equation could be used to find
rjkz [21]
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7 0
3 years ago
Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125
liq [111]

For the given equation;

(3x-5)^2=-125

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}

Now that we have expanded the left side of the equation, we would have;

\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}

ANSWER:

x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}

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solniwko [45]

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A=bh
1056=32<span>×b
</span>÷32  ÷32
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