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11Alexandr11 [23.1K]
3 years ago
10

ANSWER ASAP PLEASE. TAKE YOUR TIME TO DETERMINE IT. IT CAN HAVE MORE THAN 1 ANSWER.

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

1.) -7

A. Rational

B. Irrational

C. Natural

D. Whole

E. Integer

2.) -√81

A. Rational

B. Irrational

C. Natural

D. Whole

E. Integer

3.) 8.444....

A. Rational

B. Irrational

C. Natural

D. Whole

E. Integer

4.) 9/10

A. Rational

B. Irrational

C. Natural

D. Whole

E. Integer

5.) √42

A. Rational

B. Irrational

C. Natural

D. Whole

E. Integer

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AleksandrR [38]

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-2

Step-by-step explanation:

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Koji has 5,502 in savings this is 30 less than 6 times the amount in his checking, how much money?
omeli [17]

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3 years ago
Let f(x) = cx^k be a power function such that f(13) is four times the size of f(1). What is the power k?
Ivenika [448]

Answer:

0.540

Step-by-step explanation:

Hi there,

To get started in order to solve this, please recall the property of logarithms.

This question is a bit tricky, but doable. Best way to solve this is first compare the two functions:

f(x) = cx^{k} \\ f(13)=4f(1)  

Now, let's see what the function gives at 13 and 1:

f(13)=c13^{k}\\f(1)=c1^{k}

Something to recognize is that 1 to the power of <em>anything</em> is just 1, so f(1) is reduced to:

f(1)=c  We are making progress!

Next, we can set both f(13) forms equivalent to each other, watch this:

f(13)=f(13) = 4f(1) but we know what f(1) is equal to, and let's substitute our knowns:

c13^{k}=4c1^{k} = 4c the c constant on both left and right side cancel out:

13^{k}=4 Now, take the logarithm form of both side of the equation. I used natural log, but you can also use common logs:

ln(13^{k})=ln(4)  ⇒ k*ln(13)=ln(4) this was performed using <em>the power  log rule. </em>

Isolate k:

k=\frac{ln(4)}{ln(13)} =0.540 using a calculator.

If you liked this solution, hit Thanks or give a rating!

thanks,

8 0
3 years ago
I need this question asap ​
KengaRu [80]

Answer:

ASA

Step-by-step explanation:

congruent angle, share a side, right angle

5 0
3 years ago
PLEASE PLEASE HELP ME:(( I NEED WORKING AS WELL
mr Goodwill [35]

the equation of the line has form

y=kx+b

\left \{ {{5=k*0+b} \atop {9=k*2+b}} \right. \\b=5\\9=2k+5\\2k=4\\k=2, so

y=2x+5

The second line is parallel to the first and runs 7 units lower, so b=5

0=1k+5\\k=-5\\y=-5x+5

8 0
3 years ago
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