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4 years ago

12

The main difference between a radio wave and a sound wave is their different

1 answer:

Vaselesa [24]4 years ago

8 0

Answer:

Direction of oscillations

Explanation:

- Radio waves are part of the electromagnetic waves. Electromagnetic waves consist of oscillating electric and magnetic field. Electromagnetic waves are transverse, which means that the oscillation (of the fields) occurs in a direction perpendicular to the direction of propagation of the wave.

Electromagnetic waves are also the only type of waves that can travel through a vacuum, since they do not need a medium to propagate.

- Sound waves are mechanical waves, which consists of periodic disturbances of a medium. Sound waves are longitudinal, which means that the direction of their oscillation occurs parallel to the direction of propagation of the wave, creating alternating regions of higher density (compressions) and lower density (rarefactions) of particles.

Mechanical waves, unlike electromagnetic waves, always need a medium to propagate.

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Chang wants to build a circuit that will light up the bulb from a flashlight. Which component could Chang leave out and still li

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The type of function that describes the amplitude of damped oscillatory motion is _______. The type of function that describes t

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Answer:

exponential

Explanation:

type of function that describes the amplitude of damped oscillatory motion is exponential because as we know that here function is

y = A × $e^{\frac{-bt}{2m}}$ × cos(ωt + ∅ ) ..................................... ( 1 )

here function A × $e^{\frac{-bt}{2m}}$ is amplitude

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3 years ago

What usually results when an organism fails to maintain homeostasis?

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The organism may become ill or die

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4 years ago

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A soccer field is viewed from above, while a ball is kicked eastward with an initial speed of 10.0 m/s. The ball experiences a c

satela [25.4K]

Answer:

the ball travelled approximately 60 m towards north before stopping

Explanation:

Given the data in the question;

First course : $a_{x}$ = 0.75 m/s², $d_{x}$ = 20 m, $u_{x}$ = 10 m/s

now, form the third equation of motion;

v² = u² + 2as

we substitute

$v_{x}$ ² = (10)² + (2 × 0.75 × 20)

$v_{x}$ ² = 100 + 30

$v_{x}$ ² = 130

$v_{x}$ = √130

$v_{x}$ = 11.4 m/s

for the Second Course:

$u_{y}$ = 11.4 m/s, $a_{y}$ = -1.15 m/s², $v_{y}$ = 0

Also, form the third equation of motion;

v² = u² + 2as

we substitute

0² = (11.4)² + (2 × (-1.15) × $d_{y}$ )

0 = 129.96 - 2.3 $d_{y}$

2.3 $d_{y}$ = 129.96

$d_{y}$ = 129.96 / 2.3

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so;

|d| = √( $d_{x}$ ² + $d_{y}$ ² )

we substitute

|d| = √( (20)² + (56.5)² )

|d| = √( 400 + 3192.25 )

|d| = √( 3592.25 )

|d| = 59.9 m ≈ 60 m

Therefore, the ball travelled approximately 60 m towards north before stopping

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3 years ago

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