All categories

3 years ago

The object in this diagram has a mass of 2 kg.

Physics

1 answer:

salantis [7]3 years ago

7 0

Answer:

$4 ms^{-2}$

Explanation:

Normal force - should be the reaction from the surface it's on - nullifies the weight of the object. At this point the only force is of $22-14 = 8N$ from whoever is pushing the square and the friction, towards the right. At this point we divide the force by the mass of the object to obtain an acceleration of $8/2 = 4 ms^{-2}$

You might be interested in

Using a launch angle of zero, set the height to any value between 3-15 m. Set the horizontal velocity between 1-17 m/s and recor

ankoles [38]

Answer:It depends on the initial velocity of the projectile and the angle of projection. The maximum height of the projectile is when the projectile reaches zero vertical velocity. ... The horizontal displacement of the projectile is called the range of the projectile and depends on the initial velocity of the object

4 0

3 years ago

Describing Uses ñ Olivia wants to find out whether a substance will fluoresce. She says she should put it in a microwave oven. D

LiRa [457]

I don’t agree what if it blows up?

6 0

3 years ago

Find Vo= between the two ends of the circuit on the right.

9966 [12]

First calculate the parallel network as a single resistor and then use a voltage divider between the two resistors.

3 0

3 years ago

What horizontal speed must a pumpkin be thrown to hit a car 13.4 meters away from a building which stands 10.4 meters tall?

Ilia_Sergeevich [38]

Answer:

V₀ₓ = 9.2 m/s

Nearest answer:

D) 8.9 m/s

Explanation:

First we find the time taken by the pumpkin to hit the car. For that purpose we apply 2nd equation of motion to the pumpkin:

h = V₀y t + (1/2)gt²

where,

h = height of building = 10.4 m

V₀y = vertical component of initial speed = 0 m/s

t = time = ?

g = 9.8 m/s²

Therefore,

10.4 m = (0 m/s)(t) + (1/2)(9.8 m/s²)t²

t² = (10.4 m)(2)/(9.8 m/s²)

t = √[2.122 s²]

t = 1.45 s

Now, we analyze horizontal motion for horizontal component of initial velocity. We assume air friction to be zero so that the horizontal motion is uniform. Therefore,

s = V₀ₓ t

where,

s = horizontal distance between building and car = 13.4 m

V₀ₓ = Horizontal Component of Initial Velocity = ?

Therefore,

13.4 m = V₀ₓ(1.45 s)

V₀ₓ = 13.4 m/1.45 s

6 0

3 years ago

What is the gravitational attraction between a

Sergio [31]

Answer:

The gravitational attraction between the two objects is

Explanation:

According to universal law of gravitation, the gravitational force of attraction acting between two objects will be directly proportional to the product of mass of the objects and inversely proportional to the square of the distance of separation of two objects.

$F=\frac{GMm}{r^{2} }$

Here G is the gravitational constant, M, m are the masses of the objects given as 6564300 kg and 5640 kg. And r is the distance of separation given as 50 m.

So $F=\frac{6.674*10^{-11}*6564300*5640 }{50*50}=0.988 mN$

So the gravitational attraction of 0.988 mN will be acting between the two objects.

3 0

4 years ago