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Mama L [17]
3 years ago
14

A catcher "gives" with a baseball when catching it. If the baseball exerts a force of 475 N on the glove such that the glove is

displaced 8.97 cm, how much work is done by the ball? Answer in units of J.
Physics
1 answer:
slava [35]3 years ago
3 0

Answer:

W=42.60 J

Explanation:

Given that

F = 475 N

Acceleration due to gravity ,g= 9.8 m/s²

Height ,h= 8.97 cm = 0.0897 m ( we know 1 m = 100 cm)

As we know that work done by a force given as

W = F . d

F=force

d=Displacement

W=work done by force

Now by putting the values

W=475 x 0.0897 J

W=42.60 J

Therefore the work done by the ball will be 42.60 J.

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Xander's friend Corey has a skateboard that he rides at Newton's Skate Park.
DanielleElmas [232]

Answer:

0.5 m/s2

Explanation:

Step 1:

Data obtained from the question.

Total Mass = 60Kg

Net force = 30N

Acceleration =?

Step 2

Determination of the acceleration.

Force = Mass x Acceleration.

With the above equation, we can easily obtain the acceleration as follow:

30 = 60 x Acceleration

Divide both side by 60

Acceleration = 30/60

Acceleration = 0.5 m/s2

Now, we can thus say that the acceleration at that moment is 0.5 m/s2

8 0
4 years ago
If the mass of the ladder is 12.0 kgkg, the mass of the painter is 55.0 kgkg, and the ladder begins to slip at its base when her
Marysya12 [62]

Answer:

 μ = 0.336

Explanation:

We will work on this exercise with the expressions of transactional and rotational equilibrium.

Let's start with rotational balance, for this we set a reference system at the top of the ladder, where it touches the wall and we will assign as positive the anti-clockwise direction of rotation

          fr L sin θ - W L / 2 cos θ - W_painter 0.3 L cos θ  = 0

          fr sin θ  - cos θ  (W / 2 + 0,3 W_painter) = 0

          fr = cotan θ  (W / 2 + 0,3 W_painter)

Now let's write the equilibrium translation equation

     

X axis

        F1 - fr = 0

        F1 = fr

the friction force has the expression

       fr = μ N

Y Axis

       N - W - W_painter = 0

       N = W + W_painter

       

we substitute

      fr = μ (W + W_painter)

we substitute in the endowment equilibrium equation

     μ (W + W_painter) = cotan θ  (W / 2 + 0,3 W_painter)

      μ = cotan θ (W / 2 + 0,3 W_painter) / (W + W_painter)

we substitute the values ​​they give

      μ = cotan θ  (12/2 + 0.3 55) / (12 + 55)

      μ = cotan θ  (22.5 / 67)

      μ = cotan tea (0.336)

To finish the problem, we must indicate the angle of the staircase or catcher data to find the angle, if we assume that the angle is tea = 45

       cotan 45 = 1 / tan 45 = 1

the result is

    μ = 0.336

5 0
4 years ago
What are the particles called in a current??
aksik [14]
Electrons

although the conventional current is actually assumed to be a bunch of positive particles moving in the opposite direction
6 0
3 years ago
Read 2 more answers
A train travels 55km, south along a straight track in 34minutes. What is the train Ls average velocity in kilometers per hour
Westkost [7]

Answer:

96.5 km/h

Explanation:

The average velocity of the train is given by:

v=\frac{d}{t}

where

d is the displacement

t is the time taken

For this train, we have:

d = 55 km south (displacement is a vector, so we must also consider the direction)

t= 34 min \cdot \frac{1}{60 min/h}=0.57 h

Substituting into the equation, we find the average velocity:

v=\frac{55 km}{0.57 h}=96.5 km/h

5 0
3 years ago
A singly charged positive ion has a mass of 3.46 × 10−26 kg. After being accelerated through a potential difference of 215 V the
jasenka [17]

Answer:

1.8 cm

Explanation:

m = mass of the singly charged positive ion = 3.46 x 10⁻²⁶ kg

q = charge on the singly charged positive ion = 1.6 x 10⁻¹⁹ C

\Delta V =Potential difference through which the ion is accelerated = 215 V

v = Speed of the ion

Using conservation of energy

Kinetic energy gained by ion = Electric potential energy lost

(0.5) m v^{2} = q \Delta V\\(0.5) (3.46\times10^{-26}) v^{2} = (1.6\times10^{-19}) (215)\\(1.73\times10^{-26}) v^{2} = 344\times10^{-19}\\v = 4.5\times10^{4} ms^{-1}

r = Radius of the path followed by ion

B = Magnitude of magnetic field = 0.522 T

the magnetic force on the ion provides the necessary centripetal force, hence

qvB = \frac{mv^{2} }{r} \\qB = \frac{mv}{r}\\r =\frac{mv}{qB}\\r =\frac{(3.46\times10^{-26})(4.5\times10^{4})}{(1.6\times10^{-19})(0.522)}\\r = 0.018 m \\r = 1.8 cm

5 0
3 years ago
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