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Mama L [17]
3 years ago
14

A catcher "gives" with a baseball when catching it. If the baseball exerts a force of 475 N on the glove such that the glove is

displaced 8.97 cm, how much work is done by the ball? Answer in units of J.
Physics
1 answer:
slava [35]3 years ago
3 0

Answer:

W=42.60 J

Explanation:

Given that

F = 475 N

Acceleration due to gravity ,g= 9.8 m/s²

Height ,h= 8.97 cm = 0.0897 m ( we know 1 m = 100 cm)

As we know that work done by a force given as

W = F . d

F=force

d=Displacement

W=work done by force

Now by putting the values

W=475 x 0.0897 J

W=42.60 J

Therefore the work done by the ball will be 42.60 J.

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Hope this helps! :)

4 0
3 years ago
A light-rail commuter train accelerates at a rate of 1.35 m/s. D A 33% Part (a) How long does it take to reach its top speed of
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Answer:

a) 17.49 seconds

b) 13.12 seconds

c) 2.99 m/s²

Explanation:

a) Acceleration = a = 1.35 m/s²

Final velocity = v = 85 km/h = 85\frac{1000}{3600}=23.61\ m/s

Initial velocity = u = 0

Equation of motion

v=u+at\\\Rightarrow 23.61=0+1.35t\\\Rightarrow t=\frac{23.61}{1.35}=17.49\ s

Time taken to accelerate to top speed is 17.49 seconds.

b) Acceleration = a = -1.8 m/s²

Initial velocity = u = 23.61\ m/s

Final velocity = v = 0

v=u+at\\\Rightarrow 0=23.61-1.8t\\\Rightarrow t=\frac{23.61}{1.8}=13.12\ s

Time taken to stop the train from top speed is 13.12 seconds

c) Initial velocity = u = 23.61 m/s

Time taken = t = 7.9 s

Final velocity = v = 0

v=u+at\\\Rightarrow 0=23.61+a7.9\\\Rightarrow a=\frac{-23.61}{7.9}=-2.99\ m/s^2

Emergency acceleration is 2.99 m/s² (magnitude)

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