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Mama L [17]
3 years ago
14

A catcher "gives" with a baseball when catching it. If the baseball exerts a force of 475 N on the glove such that the glove is

displaced 8.97 cm, how much work is done by the ball? Answer in units of J.
Physics
1 answer:
slava [35]3 years ago
3 0

Answer:

W=42.60 J

Explanation:

Given that

F = 475 N

Acceleration due to gravity ,g= 9.8 m/s²

Height ,h= 8.97 cm = 0.0897 m ( we know 1 m = 100 cm)

As we know that work done by a force given as

W = F . d

F=force

d=Displacement

W=work done by force

Now by putting the values

W=475 x 0.0897 J

W=42.60 J

Therefore the work done by the ball will be 42.60 J.

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A wire carrying a current of 26.9 A is bent into a circular arc with a radius of 0.6 cm that sweeps out 0.900 radians. What is t
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The magnetic field at the center of the arc is 4 × 10^(-4) T.

To find the answer, we need to know about the magnetic field due to a circular arc.

<h3>What's the mathematical expression of magnetic field at the center of a circular arc?</h3>
  • According to Biot savert's law, magnetic field at the center of a circular arc is
  • B=(μ₀ I/4π)× (arc/radius²)
  • As arc is given as angle × radius, so

        B=( μ₀I/4π)×(angle/radius)

<h3>What will be the magnetic field at the center of a circular arc, if the arc has current 26.9 A, radius 0.6 cm and angle 0.9 radian?</h3>

B=(μ₀ I/4π)× (0.9/0.006)

  = (10^(-7)× 26.9)× (0.9/0.006)

  = 4 × 10^(-4) T

Thus, we can conclude that the magnitude of magnetic field at the center of the circular arc is 4 × 10^(-4) T.

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2 years ago
Which of the following has to happen for Earth's shadow to fall on the moon?
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2 years ago
In a machine shop, a hydraulic lift is used to raise heavy equipment for repairs. The system has a small piston with a cross-sec
Mrac [35]

Answer:

F_s=1075.9493\ N

Explanation:

Given:

  • area of piston on the smaller side of hydraulic lift, a_s=0.075\ m^2
  • area of piston on the larger side of hydraulic lift, a_l=0.237\ m^2
  • Weight of the engine on the larger side, W_l=3400\ N

Now, using Pascal's law which state that the pressure change in at any point in a confined continuum of an incompressible fluid is transmitted throughout the fluid at its each point.

P_s=P_l

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\frac{F_s}{0.075} =\frac{3400}{0.237}

F_s=1075.9493\ N is the required effort force.

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