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sweet [91]
3 years ago
6

The source of the error when a computer system fails are either the disk drive, the computer memory, or the operating system. Ve

ry often, 50% of the errors are disk drive errors, 20% are computer memory errors, and the remainder are operating system errors. From the component performance standards, the probabilities of failure due to disk drive, computer memory, and operating system errors are 0.4, 0.6 and 0.25, respectively. Given the information from the component performance standards, what is the probability of an operating system error, given that a failure occurred
Mathematics
1 answer:
faltersainse [42]3 years ago
7 0

Answer:

The probability of an operating system error given that a failure has ocurred is P(O/E)= 0.19

Step-by-step explanation:

Hello!

There are three different sources of error when a computer system fails:

D: disk drive error. ⇒ P(D)= 0.50

M: computer memory error. ⇒P(M)= 0.20

O: operating systems error. ⇒ P(O)= 0.30

According to the component perdormance standard:

The probability of failure "E", given that there is a disk drive error is P(E/D)= 0.40

The probability of failure "E", given that there is a computer memory error is P(E/M)= 0.6

The probability of failure "E", given that there is a operating system error is P(E/O)= 0.25

You need to calculate the probability of an operating system error given that a failure has ocurred, symbolically:

P(O/E)

P(O/E)= \frac{P(OnE)}{P(E)}

To reach the probability of the marginal E you have to add all intersections between the event "E" and the events "D", "M" and "O"

       D           M             O       Total

E:  P(E∩D); P(E∩M); P(E∩O);  P(E)

Using the formula of the conditional probability I'll clear all three intersections using the known probabilities:

General formula: P(A/B)= \frac{P(AnB)}{P(B)} ⇒ P(AnB)= P(A/B)*P(B)

P(E∩D)= P(E/D)*P(D)= 0.4*0.5= 0.2

P(E∩M)= P(E/M)*P(M)= 0.6*0.2= 0.12

P(E∩O)= P(E/O)*P(O)= 0.25*0.3= 0.075

P(E)= P(E∩D) + P(E∩M) + P(E∩O)= 0.2+0.12+0.075= 0.395

P(O/E)= \frac{P(OnE)}{P(E)} = \frac{0.075}{0.395}= 0.189 = 0.19

I hope it helps!

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3 years ago
Most college-bound students take either the SAT(Scholastic Assessment Test) or the ACT (which originally stood for American coll
Jlenok [28]

Answer:

Luis would need to have a SAT score of 574.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Nicole's z-score:

ACT scores have a mean of about 21 with a standard deviation of about 5, which means that \mu = 21, \sigma = 5

Nicole gets a score of 24, which means that X = 24. Her z-score is:

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 21}{5}

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What score would Luis have to have on the SAT to have the same standardized score(z-score) as Nicole's standardized score on the ACT?

Luis would have to get a score with a z-score of 0.6, that is, X when Z = 0.6.

SAT scores have a mean of about 508 with a standard deviation of about 110, which means that \mu = 508, \sigma = 110.

The score is:

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X - 508 = 0.6*110

X = 574

Luis would need to have a SAT score of 574.

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sukhopar [10]
We have that
<span> |x+6| >= 5
step 1
resolve for (x+6)>=5------> x>=5-6-------> x>= -1
the solution is the interval </span>(-1, ∞)
<span>
step 2
resolve for -(x+6) >=5------> -x-6 >=5----> -x >= 5+6---> -x>=11----> x<=-11
</span>the solution is the interval (-∞, -11)
<span>
using a graph tool
see the attached figure

the solution is the interval (-</span>∞, -11) ∩ (-1, ∞)

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Step-by-step explanation:

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