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Lady_Fox [76]
3 years ago
7

Terance galloped 20 kilometers in 40 minutes. Then he trotted 6 kilometers in 120 minutes. By how much did his first rate exceed

his second rate?
Mathematics
1 answer:
SOVA2 [1]3 years ago
5 0
20km/40min=0.5km per minute
6km/120min=6/120=1/20 or 0.05km per minute

0.5km/min is 10 times faster then 0.05km.min

His first rate exceeded his second rate by 10 times, or 1000%
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Answer:

Step-by-step explanation:

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I don't know what you mean by "Broken apart," but I'll do my best...

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I hope this helped you! :)

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2 years ago
Imena's math test scores are 83, 93, 78, 89, and 83. She has one more math test this semester. What score most she get on the te
marshall27 [118]
87 is the median because 83 and 87's average is 85.
8 0
3 years ago
Read 2 more answers
Ana has won a lottery. She was offered two options to receive the award: She can either take it in five installments of $60,000
AleksandrR [38]

Answer:

Results are below.

Step-by-step explanation:

Giving the following information:

She can either take it in five installments of $60,000 annually, starting from now; or she can take a lump-sum of $255,000 now.

<u>First, we determine the value of the 5 installments using a 5% annual compounded rate.</u>

We calculate the future value, and then the present value:

FV= {A*[(1+i)^n-1]}/i

A= annual payments

FV= {60,000*[(1.05^5) - 1]} / 0.05

FV= $331.537.88

PV= FV/(1+i)^n

PV= $259,768.60

At an annual rate of 5% compounded annually, she should choose the five installments instead of the $255,000.

<u>Now, if the annual rate is 6% continuously compounded.</u>

<u>First, we need to calculate the effective interest rate:</u>

r= e^i - 1

r= effective inerest rate

r= e^0.06 - 1

r= 0.0618

FV= {60,000*[(1.0618^5) - 1]} / 0.0618

FV= 339,443.23

PV= 339,443.23/1.0618^5

PV= $251,509.01

At an annual rate of 6% compounded continuously, she should choose the $255,000.

5 0
2 years ago
While driving from​ Chicago, Brent had a visibility problem due to the fog. After 1 1/2
liq [111]
1) Let x be the original speed that he was driving; 

x mph ---> 1.5 hours 
x+44 mph --> 2.5 hours 

1.5x + 2.5(x+44)=206 
1.5x+2.5x+110=206 
4x=206-110 
4x=96 
x=24 
Therefore, he was travelling at 24 mph in the fog. 

2) Let x be the speed of 1 snail, 
The other snail travels at the speed of x+1 cm/min 

23x+23(x+1)=391 <-- solve for x 
23x+23x+23=391 
46x=368 
x=368/46 
x=8 

Therefore one of the snail travels at 8 cm/min while the other goes at 9 cm/min 

7) Let x be one crew 
Then the other crew would be working at x+0.5 

3.2x+3.2(x0.5)=8 <-- solve for x 
3.2x+1.6x=8 
4.8x=8 
x=8/4.8 
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Therefore, one of the crew does 1.7 miles per day and the other crew does (0.5*1.7)=0.85 miles

Hope I helped :) 
5 0
3 years ago
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