Answer:
Explanation:
Rate of change of pressure with respect to heigh
= k p ( given )
= k dh
Integrating on both sides
∫ = ∫ k dh
lnp = kh + c , c is a constant
when h = 1000 m , p = 89.1 k Pa
ln 89.1 = 1000 k + c -------------- (1)
when h = 0 , p = 103.6 k Pa
ln 103.6 = 0 x k + c
c = ln 103.6
Putting it in quation (1)
ln 89.1 = 1000 k + ln103.6
ln = 1000k
k =
= - .15 x 10⁻³
lnp = - .15 x 10⁻³ h + ln 103.6
when h = 3000
lnp = - .15 x 10⁻³ x 3000 + ln 103.6
= - .45 +4.64
= 4.2
p = 66.68 k Pa
b )
when h = 6358
lnp = - .15 x 10⁻³ x 6358 + ln 103.6
= - .9537 + 4.64
= 3.6863
39.9 k Pa.