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dimulka [17.4K]
3 years ago
14

When the ratio of 2 variables is constant what can their relationship be described as

Physics
1 answer:
salantis [7]3 years ago
3 0
It can be described as a constant variation
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Which law states that the pressure and absolute temperature of a fixed quantity of gas are directly proportional under constant
Brrunno [24]

<u>Gay Lussac’s law</u> state that the pressure and absolute temperature of a fixed quantity of a gas are directly proportional under constant volume conditions.  

<h2>Further Explanation </h2><h3>Gay-Lussac’s law  </h3>
  • It states that at constant volume, the pressure of an ideal gas I directly proportional to its absolute temperature.
  • Thus, an increase in pressure of an ideal gas at constant volume will result to an increase in the absolute temperature.
<h3>Boyles’s law   </h3>
  • This gas law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at constant absolute temperature.
  • Therefore, when the volume of an ideal gas is increased at constant temperature then the pressure of the gas will also increase.
<h3>Charles’s law </h3>
  • It states that the volume of a fixed mass of a gas is directly proportional to absolute temperature at constant pressure.
  • Therefore, an increase in volume of an ideal gas causes a corresponding increase in its absolute temperature and vice versa while the pressure is held constant.
<h3>Dalton’s law  </h3>
  • It is also known as the Dalton’s law of partial pressure. It states that the total pressure of a mixture of gases is always equivalent to the total sum of the partial pressures of individual component gases.
  • Partial pressure refers to the pressure of an individual gas if it occupies the same volume as the mixture of gases.

Keywords: Gas law, Gay-Lussac’s law, pressure, volume, absolute temperature, ideal gas

<h3>Learn more about: </h3>
  1. Gay-Lussac’s law: brainly.com/question/2644981
  2. Charles’s law: brainly.com/question/5016068
  3. Boyles’s law: brainly.com/question/5016068
  4. Dalton’s law: brainly.com/question/6491675

Level: High school  

Subject: Chemistry  

Topic: Gas laws  

Sub-topic: Gay-Lussac’s law  

8 0
3 years ago
Read 2 more answers
A plane is flying east when it drops some supplies to a designated target below. The supplies land after falling for 10 seconds.
Diano4ka-milaya [45]

solution:

As Given plane is flying in east direction.

It throws back some supplies to designated target.

Time taken by the supply to reach the target =10 seconds

g = Acceleration due to gravity = - 9.8 m/s²[Taken negative as object is falling Downwards]

As we have to find distance from the ground to plane which is given by d.

d = \frac{1}{2}\times g\times t^2

 = \frac{1}{2}\times (9.8) \times(100) =50\times 9.8=490 meters

Distance from the ground where supplies has to be land  to plane  =  Option B =490 meters

6 0
3 years ago
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How do you put 1/2000 into scientific notation? *
maksim [4K]
It’s e 2.0 x 10^-4 because it is a fraction
4 0
3 years ago
A block of a plastic material floats in water with 42.9% of its volume under water. What is the density of the block in kg/m3?
adell [148]

To solve this problem we will apply the principle of buoyancy of Archimedes and the relationship given between density, mass and volume.

By balancing forces, the force of the weight must be counteracted by the buoyancy force, therefore

\sum F = 0

F_b -W = 0

F_b = W

F_b = mg

Here,

m = mass

g =Gravitational energy

The buoyancy force corresponds to that exerted by water, while the mass given there is that of the object, therefore

\rho_w V_{displaced} g = mg

Remember the expression for which you can determine the relationship between mass, volume and density, in which

\rho = \frac{m}{V} \rightarrow m = V\rho

In this case the density would be that of the object, replacing

\rho_w V_{displaced} g = V\rho g

Since the displaced volume of water is 0.429 we will have to

\rho_w (0.429V) = V \rho

0.429\rho_w= \rho

The density of water under normal conditions is 1000kg / m ^ 3, so

0.429(1000) = \rho

\rho = 429kg/m^3

The density of the object is 429kg / m ^ 3

7 0
3 years ago
A car of m = 1200. kg collides with a tree while traveling 60.0 mph. The collision occurs over a time period of 0.0500 seconds.
MrRissso [65]
You may know linear momentum is given by P= mass.velocity. Initially car is moving with some velocity so you know initial momentum of the car. Finally it comes to rest i.e final momentum of the car is 0. According to Newton's second law : Force = change in momentum /time. Applying this you'll get answer as 642840N. Hope it helped you. Revert back to me if you have any questions. Please check out the calculation it might be wrong!
5 0
3 years ago
Read 2 more answers
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