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2 years ago

CCL4 is Non polar and NH3 is Polar? Why?

Physics

1 answer:

lys-0071 [83]2 years ago

6 0

Answer:

CCL4 is non polar cause' they are equal covalent bonds between carbon and chlorine.
The electronegativity difference between hydrogen and nitrogen is about .9 which is a pretty polar bond. So each N-H bond is definitely polar. But NH3 is also asymmetrical .

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Explanation:

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A charge of 7.00 mC is placed at opposite corners corner of a square 0.100 m on a side and a charge of -7.00 mC is placed at oth

andrew-mc [135]

Answer:

4.03\times10^{7}N[/tex], 135°

Explanation:

charge, q = 7 mC = 0.007 C

charge, - q = - 7 mC = - 0.007 C

d = 0.1 m

Let the force on charge placed at C due to charge placed at D is FD.

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The direction of FB is along C to B.

Let the force on charge placed at C due to charge placed at A is FA.

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The direction of FA is along A to C.

The net force along +X axis

$F_{x}=F_{A}Cos45-F_{D}$

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The net force along +Y axis

$F_{y}=F_{B}-F_{A}Sin45$

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The resultant force is given by

$F=\sqrt{F_{x}^{2}+F_{y}^{2}}=\sqrt{(-2.85\times10^{7})^{2}+(2.85\times10^{7})^{2}}$

$F = 4.03\times10^{7}N$

The angle from x axis is Ф

tan Ф = - 1

Ф = -45°

Angle from + X axis is 180° - 45° = 135°

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Answer:

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ololo11 [35]

Answer:

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From the options, only options A & D fits this definition of single-displacement reactions.

For option D: Both left and hand and right hand sides each have one element and one compound. We can see that K is substituted from KBr to join Cl to form KCl and Br2 on the right hand side.

For option A: Both left and hand and right hand sides each have one element and one compound. We can see that OH is substituted from 2H2O to join Mg to form Mg(OH)2 and H2 on the right hand side.

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CCL4 is Non polar and NH3 is Polar? Why?​

CCL4 is Non polar and NH3 is Polar? Why?