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3 years ago

What two numbers multiply to 20 and add up to 17

1 answer:

4 0

That is not possible, since 20 has the factors of 1,2,4,5,10, and 20. None of those add up to 17, maybe your question has a mistake in it. For further questions, you can message me. Hope this helps! Please rate brainiest answer.

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HELP PLZZZZZZZ!!! Compute: -3^4 • 5

Kipish [7]

Answer:

405

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If a > b > c > d, then which is larger, a+c or b+d ? Can we tell from a > b > c > d which of a+d and b+c is la

victus00 [196]

Answer:

1. a+c is larger than b+d

2. No way to tell whether a+d or b+c is larger.

Step-by-step explanation:

1. Which is larger, a+c or b+d?

Let a, b, c, and d be any numbers such that $a > b > c > d$ .

Specifically, note that $a > b$ , and subtracting b from both sides of the inequality, observe that $a-b > 0$ .

Similarly, $c > d$ , and subtracting d from both sides of the inequality, observe that $c-d > 0$ .

From this, add "a-b" (a positive number, as proven above) to both sides of the inequality.

$(a-b)+(c-d) > (a-b)+0$

Addition by zero (the additive identity) doesn't change anything, so the right side remains "a-b"...

$(a-b)+(c-d) > a-b$

... and "a-b" is positive...

$(a-b)+(c-d) > a-b > 0$

... so, by the transitive property of inequality...

$(a-b)+(c-d) > 0$

Recall that subtraction is addition by a negative number...
$a+(-b)+c+(-d) > 0$

...and that addition is associative and commutative, so things can be added in any order, so the middle two terms on the left side can be rearranged...

$a+c+(-b)+(-d) > 0$

Adding b + d to both sides of the inequality

$(a+c+(-b)+(-d))+(b+d) > 0+(b+d)$

... and simplifying

$a+c > b+d$

So, a+c is larger than b+d.

2. Which is larger, a+d or b+c?

Consider the following two examples:

Example 1

Suppose a=10; b=3; c=2; d=1.

Note that $a > b > c > d$ ( $10 > 3 > 2 > 1$ ) and, also observe that $a+d=(10)+(1)=11$ , and $b+c=(3)+(2)=5$ , so a+d is larger than b+c.

Example 2

However, suppose a=10; b=9; c=8; d=1.

Note that $a > b > c > d$ ( $10 > 9 > 8 > 1$ ) but that $a+d=(10)+(1)=11$ , and $b+c=(9)+(8)=17$ , so a+d is smaller than b+c.

So, in one example, a+d is bigger, and in the other, a+d is smaller. Therefore, there is no way to tell which of a+d or b+c is larger from only the given information.

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2 years ago

According to the graph, what has been taking place within India's economy since 2005? During which years does India's developmen

Alja [10]

Answer:

1. rapid development

2. 2007-2010

Step-by-step explanation:

just did it edge hope this helps :))

6 0

3 years ago

Read 2 more answers

Twice a number added to 13 is equal to 27 what is the number

STALIN [3.7K]

Let's think that The NUMBER is x so it would be 2x+13=27 so this goes to 2x=27-13 which is 2x=14 so x equal to 7

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2 years ago

Multiply. Your answer should be a monomial in standard form. {(-t^7)(-t^5)}

allochka39001 [22]

Answer:

t^12

Step-by-step explanation:

Because both multiplicands are negative, their product will be positive. Both multiplicands are to the same base: t.

Therefore, the product is t^(7 + 5), or t^12.

6 0

3 years ago