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3 years ago

HELP ME PLZ I NEED IT

Mathematics

2 answers:

Alchen [17]3 years ago

4 0

Answer:

= 12 cm^3

Step-by-step explanation:

V = Bh where B is the area of the base and h is the height

For a triangular prism, the base is the triangle

A = 1/2 bh for the triangle

= 1/2 (6*2)

= 6 cm^2

To find the volume for the triangular prism

V = Bh

= 6 * 2

= 12 cm^3

Slav-nsk [51]3 years ago

3 0

Answer:

12 cm³

Step-by-step explanation:

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HELP DUE IN 10 MINS!

Scilla [17]

Answer:

$\checkmark \text{B. The area of the circle is } 729\pi,\\\checkmark \text{D. The arc length of the sector is } 12\pi$

Step-by-step explanation:

Area of a circle with radius $r$ : $r^2\pi$

Circumference of a sector with radius $r$ : $2r\pi$

Area of sector with angle $\theta$ : $r^2\pi\cdot \frac{\theta}{360}$ .

Arc length of sector with angle $\theta$ : $2r\pi\cdot \frac{\theta}{360}$

Using these equations, we get the following information:

Area of circle: $27^2\pi=729\pi$

Circumference of a circle: $2\cdot 27\cdot \pi=54\pi$

Area of sector: $27^2\pi\cdot \frac{80}{360}=162\pi$

Arc length of sector: $2\cdot 27\cdot \pi \cdot \frac{80}{360}=12\pi$

3 0

3 years ago

Can someone please help me solve these 4

choli [55]

Answer:

find the area and then multiply

Step-by-step explanation:

5 0

2 years ago

Find the perimeter of the triangle. Please help! That one is 2x+5 if you cannot see.

Paul [167]

2x3x5=30
3 is from the amount of sides in the triangle

6 0

4 years ago

I just need the advance ticket price iknow that the same day is 15$

OverLord2011 [107]

I would feel better if you'd explain how you "know" that a "same-day" ticket is $15.

"The combined cost of one advance ticket and one same-day ticket is $35." This would imply that the cost of one advance ticket is $(35-15), or $10.

Check by substitution to determine whether $15 and $10 are correct. If not, please show your work, so that someone else or I could step back in and help.

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3 years ago

SOMEONE PLEASE HELP ME!!!!! I NEED THIS!

snow_tiger [21]

Answer:

QR ≈ 16.3

Step-by-step explanation:

Since the figures are similar then the ratios of corresponding sides are equal, that is

$\frac{MN}{QR}$ = $\frac{MP}{QT}$ , substitute values