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Fofino [41]
3 years ago
9

Ax^2+bx+c=0, where a,b,and c are rational numbers and the quadratic has two distinct zeros

Mathematics
1 answer:
wariber [46]3 years ago
6 0

Answer:

Step-by-step explanation:

ax^2+bx+c=0    ...   a≠0

a,b,and c are rational numbers

the quadratic has two distinct zeros when : delta ≻0    delta = b²- 4ac

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Find the value of x (circles)
Marrrta [24]

Answer:

x = 55

Step-by-step explanation:

opposite angles are supplementary

125+x = 180

Subtract 125 from each side

125+x-125 = 180-125

x = 55

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3 years ago
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What ie mesurement and writes its important​
Mekhanik [1.2K]

Step-by-step explanation:

A measurement is the action of measuring something, or some amount of stuff. So it is important to measure certain things right, distance, time, and accuracy are all great things to measure. By measuring these things or in other words, by taking these measurements we can better understand the world around us.

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3 years ago
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Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if
Alborosie
\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}

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4 0
3 years ago
Anna has a total of 36 goldfish in her aquarium, some are orange and some are black. The number of orange goldfish is 7 more tha
andriy [413]

Answer:

x + y = 36.....Equation 1

x = 7 + 2y...... Equation 2

Step-by-step explanation:

Let the number of:

Orange goldfish = x

Black gold fish = y

Anna has a total of 36 goldfish in her aquarium, some are orange and some are black.

x + y = 36.....Equation 1

The number of orange goldfish is 7 more than twice the number of black goldfish.

x = 7 + 2y...... Equation 2

We can rewrite this as:

x - 2y = 7..... Equation 2

The system of equations below that can be used to describe the number of black and orange goldfish in Anna's aquarium is :

x + y = 36.....Equation 1

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3 0
2 years ago
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If you raise 4 to the 214th power, what is the units digit of the result
Len [333]
\begin{array}{lrlll}
4^1&\boxed{4}\\
4^2&1\boxed{6}\\
4^3&6\boxed{4}\\
4^4&25\boxed{6}\\
4^5&102\boxed{4}\\
4^6&409\boxed{6}
\end{array}\impliedby \textit{see the pattern for 4?}

notice, it goes 4,6 then 4, 6 again, and so on and so on
based on whatever exponent it may have

now, you're being asked, what 214 will give? 4 or 6?
4 0
3 years ago
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