The range that the amount withheld vary if the weekly wages, after subtracting withholding allowances, vary from $600 to $700 inclusive is: 76.35<x<101.35.
<h3>Range</h3>
Given
592<x1317
74.35+.25
Hence:
Lowest range
74.35+.25(600-592)
74.35+.25(8)
74.35+2
=76.35
Highest range
74.35+.25(700-592)
74.35+.25(108)
74.35+27
=101.35
Range
76.35<x<101.35
Therefore the range that the amount withheld vary if the weekly wages, after subtracting withholding allowances, vary from $600 to $700 inclusive is: 76.35<x<101.35.
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Answer:
12
Step-by-step explanation:
We know that AD=BC and that AB=CD. We also know the perimeter of the rectangle ABCD to be 54 units.
From this, we can add up the sides which will be equal to 54 units.
AD+BC+AB+CD=54
2x+2x+3x-3+3x-3=54
10x=60
x=6
Since we are trying to find the length of side BC we substitute this value back into 2x.
BC=2x =2*6=12
Therefore, the length of BC is 12 units.
3÷?=36
multiply both sides by 3 to figure out what "?" is
36*3=108
3÷108=36
?=108
You first do 3 + 2, which would equal 5. Then, you would just do 3/5.
Answer:
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Step-by-step explanation:
First use
It doesn't have to be , it could be . It will be the same answer.
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