this is approximately 6 to 200
divide both by 2
3 to 100
3 to 10^2
3 out of 100
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:
302
Step-by-step explanation:
Answer:
Step-by-step explanation:
A(-1, 2) ==> A'(-2, 4)
B(3,1) ==> B'(6,2)
C(1,-4) ==> C'(2,-8)
Based on the results of each set, the scale factor is 2
A(-1*2, 2*2)= A'(-2, 4)
Answer:
Step-by-step explanation:
We are given the equation 
. To find y-value when or at x = 3, simply substitute x = 3 in which gives us 
then evaluate the value as we obtain the y-value or final answer to the question:
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