Average rate of change over interval [a,b]: r=[f(b)-f(a)]/(b-a)
In this case the interval is [0,2], then a=0, b=2
r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2
1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
r=4
2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
r=(0+10)/2
r=(10)/2
r=5
3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
g(0)=2
r=(6-2)/2
r=(4)/2
r=2
4) Fourth function: j(x)
r=[j(2)-j(0)]/2
From the table:
x=2→j(2)=-8
x=0→j(0)=4
r=(-8-4)/2
r=(-12)/2
r=-6
Answer:
Pairs
1) h(x) 4
2) f(x) 5
3) g(x) 2
4) j(x) -6
Answer:
help with what
Step-by-step explanation:
Answer:
55,98,27
Step-by-step explanation:
To solve for the angles we must first find y with this equation
3y+5+2y-7=153
We can simplify this
5y-2=153
153+2=155
155/5=31
y=31
We now know y and can plug it into the angles
<A=2y-7
2(31)-7
62-7
55
<A=55
<B=3y+5
3(31)+5
93+5
98
<B=98
Now time for the last angle
Since angle BCA and DCB are next to each other they add up to 180
153+x=180
180-153=27
x=27
<BCA=27
Answer:
Test's average-95
Homework's average-96.67
Step-by-step explanation:
Average is mathematically defined as the sum of the values divided by the total number of values and is expressed as:
The Tests' average is calculated as:
Hence, the Tests' average is 95
#The Homework's average is calculated as:
Hence, the Homework's average is 96.67
Answer:
x= 3 over 10 =0.300
Step-by-step explanation:
Hope this helps!
